
The Coefficient of variance of a distribution is $80\% $ and the mean of the distribution is $40$, the Standard Deviation of the distribution is?
Answer
484.5k+ views
Hint: Here we have to find out the standard deviation of the distribution.
So, we have to use the given data to find out by using the formula for coefficient of variance.
First we have to convert the data into decimal form.
Then we do some simplification and we get the required answer.
Formula used: ${\text{C}}{\text{.V = }}\dfrac{{{\sigma }}}{{{\mu }}}$, Where ${\text{C}}{\text{.V}}$ is the coefficient of Variance $\mu $ is the mean of the distribution and $\sigma $ is the Standard deviation.
Complete step-by-step solution:
It is given in the question stated as Mean $\mu = 40$ and,
Coefficient of Variance ${\text{C}}{{.V = 80\% }}$
Now we have to converting from Percentage to decimal we get,
${\text{C}}{\text{.V = }}\dfrac{{{\text{80}}}}{{{\text{100}}}}{\text{ = 0}}{\text{.8}}$
After that we have to use the formula for coefficient of variance,
${\text{C}}{\text{.V = }}\dfrac{{{\sigma }}}{{{\mu }}}$
Putting the values and we get,
$ \Rightarrow 0.8 = \dfrac{\sigma }{{40}}$
On taking cross multiplication, we have to find out the value for standard deviation $\sigma $ we get:
$ \Rightarrow \sigma = 0.8 \times 40$
Let us multiply the term we get,
$ \Rightarrow \sigma = 32$
Hence we get the value of standard deviation.
$\therefore $ The Standard Deviation of a distribution with means $40$ and C.V. ${{80\% }}$ is $32$
Note: A place where the solution could go wrong is converting the coefficient from percentage to decimal, coefficient of variance is always measured in terms of percentage.
Remembering the formula of the relation between the Coefficient of Variation, mean and the standard deviation of a distribution.
Coefficient of Variance measures the degree of dispersion of the overall data around the mean; it is represented as the ratio of the standard deviation to the mean.
So, we have to use the given data to find out by using the formula for coefficient of variance.
First we have to convert the data into decimal form.
Then we do some simplification and we get the required answer.
Formula used: ${\text{C}}{\text{.V = }}\dfrac{{{\sigma }}}{{{\mu }}}$, Where ${\text{C}}{\text{.V}}$ is the coefficient of Variance $\mu $ is the mean of the distribution and $\sigma $ is the Standard deviation.
Complete step-by-step solution:
It is given in the question stated as Mean $\mu = 40$ and,
Coefficient of Variance ${\text{C}}{{.V = 80\% }}$
Now we have to converting from Percentage to decimal we get,
${\text{C}}{\text{.V = }}\dfrac{{{\text{80}}}}{{{\text{100}}}}{\text{ = 0}}{\text{.8}}$
After that we have to use the formula for coefficient of variance,
${\text{C}}{\text{.V = }}\dfrac{{{\sigma }}}{{{\mu }}}$
Putting the values and we get,
$ \Rightarrow 0.8 = \dfrac{\sigma }{{40}}$
On taking cross multiplication, we have to find out the value for standard deviation $\sigma $ we get:
$ \Rightarrow \sigma = 0.8 \times 40$
Let us multiply the term we get,
$ \Rightarrow \sigma = 32$
Hence we get the value of standard deviation.
$\therefore $ The Standard Deviation of a distribution with means $40$ and C.V. ${{80\% }}$ is $32$
Note: A place where the solution could go wrong is converting the coefficient from percentage to decimal, coefficient of variance is always measured in terms of percentage.
Remembering the formula of the relation between the Coefficient of Variation, mean and the standard deviation of a distribution.
Coefficient of Variance measures the degree of dispersion of the overall data around the mean; it is represented as the ratio of the standard deviation to the mean.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Economics: Engaging Questions & Answers for Success

Trending doubts
State and prove Bernoullis theorem class 11 physics CBSE

What is the difference between superposition and e class 11 physics CBSE

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

State the laws of reflection of light

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells
