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We need to use a unitary method in this case. In unitary method if we know price of a particular product, we can find price of number of products by multiplication, also we can price of single product if we are given with price of number of products with division.

If S.P \[ > \] C.P then there will be profit.

If C.P \[ > \] S.P then there will be loss.

Given,

Cost of \[50l\]cask of Wine \[ = Rs.6250\]

Selling price of \[1l\] wine \[ = Rs.130\]

Cost price of \[50l\]wine \[ = Rs.6250\]

Cost price of \[1l\]wine \[ = Rs.\dfrac{{6250}}{{50}} = Rs.125\]

We were given the Cost Price of \[50l\] wine. Hence by unitary method we got the Cost Price of \[1l\] wine i.e. \[Rs.125\]by division.

We have,

Cost price of \[1l\] wine \[ = Rs.125\] …… (i)

Selling price of \[1l\] wine \[ = Rs.130\] …… (ii)

As, Selling Price \[ > \] Cost Price

We have, Profit \[ = Selling\\Price - \,\operatorname{Cos} tPrice\]

Using, value from (i) and (ii)

Profit \[ = \,Rs.130 - Rs.125\]

Hence, Profit \[ = \,Rs.5\]

The gain percent \[ = \,\]\[\dfrac{{Gain(Profit)}}{{C.P}} \times 100\]

Put Profit \[ = 5\] and C.P \[ = 125\]

Gain \[\% = \dfrac{1}{{25}} \times 100 = 4\% \]

Therefore, the merchant gad \[4\% \] profit.

\[C.P = \dfrac{{100}}{{100 + P\% }} \times S.P\]

Never Confuse C.P with S.P where C.P means the cost price whereas the S.P means selling price.