The charge on cobalt in ${[Co{(CN)_6}]^{3 - }}$ is:
A. $ - 6$
B. $ - 3$
C. $ + 3$
D. $ + 6$
Answer
645.6k+ views
Hint: In the compound the cyanide group is present which has charge equal to $ - 1$. And we know that the transition elements can show more than one type of valency so here we have to use charge balance to calculate the charge on cobalt.
Complete step by step answer:
First of all we will read about transition elements.
Transition elements: Those elements which are in groups from three to eleven. They are called a transition because they are in between the s- block elements and p-block elements. For example: Scandium, iron, zinc, etc. They have fully or at least one electron in their d-orbits. For example: scandium has one d-electron, zinc has ten d-electrons. Due to the different number of electrons present in their d-shells they show different valencies. For example: Scandium having one electron can show three valencies as one, two and three. Because the atomic number of scandium is $21$and its electronic configuration is $Ar3{d^1}4{s^2}$. By losing only one s-electron it will attain one valency and by losing both the s-electrons it will attain valency two. And by losing two s-electrons and one d-electron it will achieve three valencies which is a stable state of scandium. Because after losing three electrons it will attain electronic configuration of noble gas argon.
In the question we are given the compound of cobalt. We know that the atomic number of cobalt is $27$. So its electronic configuration will be $Ar3{d^7}4{s^2}$. So it can show a number of valencies by losing seven d-electrons and two s-electrons. In the compound given in the question cyanide group is attached to the cobalt. And the charge on the cyanide group is $ - 1$. So the total charge due to the cyanide groups will be $ - 6$. Now the whole charge of the compound is given as $ - 3$. And let the charge on cobalt be $x$. Then the total charge due to the cobalt and cyanide groups must be equal to $ - 3$.
So,
$
\Rightarrow \ x - 6 = - 3 \\
\Rightarrow\ x = 3 \\
$
So, the correct answer is Option C .
Note:
Ligands: These are the molecules which form bonds with the central metal atom or ions. They can be of two types based on electron pair donor or acceptor. If they accept electron pair i.e. ligand is electron pair acceptor then it is Lewis acid and if it is electron pair donor then they will be Lewis base.
Complete step by step answer:
First of all we will read about transition elements.
Transition elements: Those elements which are in groups from three to eleven. They are called a transition because they are in between the s- block elements and p-block elements. For example: Scandium, iron, zinc, etc. They have fully or at least one electron in their d-orbits. For example: scandium has one d-electron, zinc has ten d-electrons. Due to the different number of electrons present in their d-shells they show different valencies. For example: Scandium having one electron can show three valencies as one, two and three. Because the atomic number of scandium is $21$and its electronic configuration is $Ar3{d^1}4{s^2}$. By losing only one s-electron it will attain one valency and by losing both the s-electrons it will attain valency two. And by losing two s-electrons and one d-electron it will achieve three valencies which is a stable state of scandium. Because after losing three electrons it will attain electronic configuration of noble gas argon.
In the question we are given the compound of cobalt. We know that the atomic number of cobalt is $27$. So its electronic configuration will be $Ar3{d^7}4{s^2}$. So it can show a number of valencies by losing seven d-electrons and two s-electrons. In the compound given in the question cyanide group is attached to the cobalt. And the charge on the cyanide group is $ - 1$. So the total charge due to the cyanide groups will be $ - 6$. Now the whole charge of the compound is given as $ - 3$. And let the charge on cobalt be $x$. Then the total charge due to the cobalt and cyanide groups must be equal to $ - 3$.
So,
$
\Rightarrow \ x - 6 = - 3 \\
\Rightarrow\ x = 3 \\
$
So, the correct answer is Option C .
Note:
Ligands: These are the molecules which form bonds with the central metal atom or ions. They can be of two types based on electron pair donor or acceptor. If they accept electron pair i.e. ligand is electron pair acceptor then it is Lewis acid and if it is electron pair donor then they will be Lewis base.
Recently Updated Pages
Explain the structure of megasporangium class 12 biology CBSE

Why is chloroform kept in dark coloured bottles class 12 chemistry CBSE

Derive the balancing condition of a Wheatstone bri class 12 physics CBSE

Draw VI characteristics of a pn junction diode Explain class 12 physics CBSE

Is it possible to carry pride in ones language too class 12 english CBSE

In a population at Hardy Weinberg equilibrium the allele class 12 biology CBSE

Trending doubts
Which are the Top 10 Largest Countries of the World?

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Which animal never drinks water in its entire life class 12 biology CBSE

The first microscope was invented by A Leeuwenhoek class 12 biology CBSE

How many structural isomers of C5H10O are there class 12 chemistry CBSE

Derive an expression for the electric field intensity class 12 physics CBSE

