
The catalogue price of a computer set is Rs.45,000. The shopkeeper gives a discount of 7% on the listed price. He gives a further off-season discount of 4% on the balance. However, Sales Tax at 8% is charged on the remaining amount. Find the amount of Sales Tax a customer has to pay,
A. The amount of Sales Tax a customer has to pay = Rs.3,164.08
B. The amount of Sales Tax a customer has to pay = Rs.3,214.08
C. The amount of Sales Tax a customer has to pay = Rs.3,355.08
D. The amount of Sales Tax a customer has to pay = Rs.3,572.08
Answer
599.1k+ views
Hint: First of all, find the discount price given by the shopkeeper and then find the sale price by removing the price of off-season discount from the remaining price after reducing the discount price given by the shopkeeper. Then find 8% of the sale price which is the required amount of Sales Tax which has to be paid by a customer.
Complete step-by-step answer:
Given list price of a computer set = Rs.45,000
Discount given by shopkeeper = 7%
Discount price = 7% of Rs.45,000
\[ = \dfrac{7}{{100}} \times 45000 = Rs.3,150\]
So, the price after discount = list price – discount price
= Rs.45,000 – Rs.3,150
= Rs.41,850
And the shopkeeper gave off-season discount of 4%
Off-season discount price = 4% of Rs.41,850
\[ = \dfrac{4}{{100}} \times 41850 = Rs.1,674\]
So, the sale price after off-season discount = discount price – off-season discount price
= Rs.41,850 – Rs.1.674
= Rs.40,176
Now, the customer has to pay a Sales Tax of 8%.
So, 8% of Rs.40,176 \[ = \dfrac{8}{{100}} \times 40176 = Rs.3,214.08\]
Thus, the amount of Sales Tax a customer has to pay is Rs.3,214.08
Hence the correct option is B. The amount of Sales Tax a customer has to pay = Rs.3,214.08
Note: \[x\% \] of \[y\] is given by \[\dfrac{x}{{100}} \times y\]. Most of the students tend to do wrong by calculating the final sale price by subtracting the amount of discount price and off-season price from the listed price at a time. So, don’t make such types of mistakes.
Complete step-by-step answer:
Given list price of a computer set = Rs.45,000
Discount given by shopkeeper = 7%
Discount price = 7% of Rs.45,000
\[ = \dfrac{7}{{100}} \times 45000 = Rs.3,150\]
So, the price after discount = list price – discount price
= Rs.45,000 – Rs.3,150
= Rs.41,850
And the shopkeeper gave off-season discount of 4%
Off-season discount price = 4% of Rs.41,850
\[ = \dfrac{4}{{100}} \times 41850 = Rs.1,674\]
So, the sale price after off-season discount = discount price – off-season discount price
= Rs.41,850 – Rs.1.674
= Rs.40,176
Now, the customer has to pay a Sales Tax of 8%.
So, 8% of Rs.40,176 \[ = \dfrac{8}{{100}} \times 40176 = Rs.3,214.08\]
Thus, the amount of Sales Tax a customer has to pay is Rs.3,214.08
Hence the correct option is B. The amount of Sales Tax a customer has to pay = Rs.3,214.08
Note: \[x\% \] of \[y\] is given by \[\dfrac{x}{{100}} \times y\]. Most of the students tend to do wrong by calculating the final sale price by subtracting the amount of discount price and off-season price from the listed price at a time. So, don’t make such types of mistakes.
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