
The atom having the valence shell electronic configuration $4{s^2}4{p^2}$ would be in:
(A) Group IIA and period 3
(B) Group IIB and period 4
(C) Group IVA and period 4
(D) Group IV A and period 3
Answer
546.6k+ views
Hint:At the point when components are organized by their nuclear number, there is a periodicity in properties of components. The peculiarities found in Mendeleev's intermittent table was taken out. The isotopes were given positions. The nuclear loads are organized all together.
Complete answer:
The particle having the valence shell electronic design $4{s^2}4{p^2}$ would be in Group $IVA$ and 4 period. $'n'$ in electronic arrangement portrays the period and the valence electrons portrays the gathering number. The advanced periodic table depends on the electronic setup of the components. The properties of a component are resolved generally by the electrons in its peripheral or valence shell. Valence electrons associate with different iotas and partake in every substance response, while inward shell electrons have little impact on the properties of components. At the point when components are put in at the request of their expanding nuclear number, the components having a similar number of valence shell electrons are rehashed in such a manner, to fall under a similar gathering. Since, the electronic setup of the valence shell electrons is the same they show comparative properties.
Additional information:
What is modern periodic law?The law that the properties of the components are occasional elements of their nuclear numbers. A table of the substance components orchestrated arranged by nuclear number, normally in lines, so components with comparable nuclear structure (and henceforth comparative compound properties) show up in vertical sections.
Hence the correct answer is (C).
Note:The advanced occasional table depends on the electronic setup of the components. The properties of a component are resolved generally by the electrons in its furthest or valence shell. Valence electrons interface with different particles and partake in every single substance response, while inward shell electrons have little effect on the properties of components.
Complete answer:
The particle having the valence shell electronic design $4{s^2}4{p^2}$ would be in Group $IVA$ and 4 period. $'n'$ in electronic arrangement portrays the period and the valence electrons portrays the gathering number. The advanced periodic table depends on the electronic setup of the components. The properties of a component are resolved generally by the electrons in its peripheral or valence shell. Valence electrons associate with different iotas and partake in every substance response, while inward shell electrons have little impact on the properties of components. At the point when components are put in at the request of their expanding nuclear number, the components having a similar number of valence shell electrons are rehashed in such a manner, to fall under a similar gathering. Since, the electronic setup of the valence shell electrons is the same they show comparative properties.
Additional information:
What is modern periodic law?The law that the properties of the components are occasional elements of their nuclear numbers. A table of the substance components orchestrated arranged by nuclear number, normally in lines, so components with comparable nuclear structure (and henceforth comparative compound properties) show up in vertical sections.
Hence the correct answer is (C).
Note:The advanced occasional table depends on the electronic setup of the components. The properties of a component are resolved generally by the electrons in its furthest or valence shell. Valence electrons interface with different particles and partake in every single substance response, while inward shell electrons have little effect on the properties of components.
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