
The area of a triangle region with a base of $ 32cm $ is $ 288sq.cm $ . Find its height.
Answer
521.4k+ views
Hint: First we have to define what the terms we need to solve the problem are.
Area means quantitative or else like a measurement. A triangle is three sides closed vertices or like angles with $ 2D $ , \[2\]dimensional shapes.
Complete step by step answer:
First, we need to know how to find the area of the triangle for the given problem, which is the total surface or else like a space enclosed by three lines of boundaries of the triangle, is called as or known as area of the triangle. If base and height of a triangle are given then we need to calculate the total area of triangle, but here in this problem we clearly see that area of triangle and the base are given
So, we need to calculate the height as the area of a triangle region with a base of $ 32cm $ is $ 288sq.cm $ .
Hence the formula for area of triangle is Area of triangle = half of length of base into length of height
Which is $ Area = \dfrac{1}{2}(base)(height) $ here we know the base value and the area of triangle
So, we are going to substitute into the formula to get height of the given problem
Therefore $ Area = \dfrac{1}{2}(base)(height) \Rightarrow 288 = \dfrac{1}{2}(32)(height) $ and cross multiplied we get
$ Height = \dfrac{{288}}{{16}} = 18cm $ (Solving the 288 which is divided by \[16\]using division method and we get the quotient as\[18\])
Hence the height of the given region is $ 18cm $
Note: On finding the area of triangle or length of the base or length of height we use the same formula but the only difference is substituting the known values to get the unknown value like above. Suppose if base is the unknown, substitute the area of triangle and height values to find it.
Area means quantitative or else like a measurement. A triangle is three sides closed vertices or like angles with $ 2D $ , \[2\]dimensional shapes.
Complete step by step answer:
First, we need to know how to find the area of the triangle for the given problem, which is the total surface or else like a space enclosed by three lines of boundaries of the triangle, is called as or known as area of the triangle. If base and height of a triangle are given then we need to calculate the total area of triangle, but here in this problem we clearly see that area of triangle and the base are given
So, we need to calculate the height as the area of a triangle region with a base of $ 32cm $ is $ 288sq.cm $ .
Hence the formula for area of triangle is Area of triangle = half of length of base into length of height
Which is $ Area = \dfrac{1}{2}(base)(height) $ here we know the base value and the area of triangle
So, we are going to substitute into the formula to get height of the given problem
Therefore $ Area = \dfrac{1}{2}(base)(height) \Rightarrow 288 = \dfrac{1}{2}(32)(height) $ and cross multiplied we get
$ Height = \dfrac{{288}}{{16}} = 18cm $ (Solving the 288 which is divided by \[16\]using division method and we get the quotient as\[18\])
Hence the height of the given region is $ 18cm $
Note: On finding the area of triangle or length of the base or length of height we use the same formula but the only difference is substituting the known values to get the unknown value like above. Suppose if base is the unknown, substitute the area of triangle and height values to find it.
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