Question

The aqueous solution of copper (ii) sulphate is slowly hydrolyzed forming basic copper sulphate whose chemical composition is
(A) $CuS{O_4}.Cu{(OH)_2}$
(B) $CuS{O_4}.CuO$
(C) $CuS{O_4}.Cu{(OH)_2}.CuO$
(D) $[Cu{({H_2}O)_4}]S{O_4}.{H_2}O$

Answer 1

Hint:At first we will see what is copper sulphate and its chemical formula. Then we will see what happens when the copper sulphate is mixed into the water. Then we will write a chemical reaction. We will find that a basic copper sulphate as given in question is formed and from that reaction resultants we can see the chemical formula of the basic copper sulphate.

Complete step-by-step answer:Step1. We have given with the copper sulphate in the question. It is an inorganic compound. Its chemical composition is $CuS{O_4}$. It is often called with different names with times like blue vitriol, vitriol of copper, bluestone. It is bright and blue in nature.
Step2. Now when it is slowly mixed into the water, it will break into the ions of copper and sulphate. The hydroxide ion will pair with one ion of copper and one ion of copper will again get paired with sulphate ion. The hydrogen ion and sulphate ion will be left stranded in water.
Step3. The reaction is mentioned below:
$2CuS{O_4} + 2{H_2}O \to CuS{O_4}.Cu{(OH)_2} + 2{H^ + } + SO_4^{2 - }$
Step4. $CuS{O_4}.Cu{(OH)_2}$ is the desired resultant we have got. It is the basic form of copper sulphate.

Hence by looking at all the options we can say that option A is the correct Option.

Note:It is an excellent answer to most fungi, it is used as fungicide. A lot of chemical tests use the copper sulphate, It is used in Benedict’s solution to test for reducing sugars. It is also used to test the blood for a disease called anemia.