Question

The angular shape of the molecule $\left( {{O_3}} \right)$ consists of :
A. $1$ sigma and $1$ pi bond
B. $2$ sigma and $1$ pi bond
C. $1$ sigma and $2$ pi bond
D. $2$ Sigma and $2$ pi bond

Answer 1

Hint: The angular shape of a molecule is dependent on the molecular geometry of that molecule. One can think about what molecular geometry of the ozone molecule can be and decide its structure on that. After getting the shape one can decide the number of double bonds and the number of sigma bonds the molecule has in its structure.

Complete step by step answer:
-First of all we will learn about what the angular shape of a molecule means, an angular shape means having one or more sharp angles in the molecule. In the angular shape of the molecule, the bonds and lone pair present in the molecule are considered.
-Now let's learn about how to find out the angular shape of the ozone molecule i.e. ${O_3}$. The ozone molecule has $s{p^3}$ hybridization which shows there are two bond pairs present and two lone pairs present on the central oxygen atom.
-Let us see the structure of ozone from the above information,

-Now after analyzing the above structure we came to know that the angular shape of the molecule $\left( {{O_3}} \right)$ has $2$ sigma and $1$ pi bond which shows option B as a correct choice of answer.

Note: The single sigma bond between the two oxygen atoms shows the coordinate bond. The geometry of the ozone molecule is trigonal planar. The ozone molecule shows the bent angle ${116.8^0}$ and the distance between the bond of oxygen atoms is $128{\text{ pm}}$ (picometer). The presence of lone pairs on the central oxygen atom which repels the electrons present in the two bonds makes the molecule show the bent molecular geometry.