
The alkyne which will react with \[KMn{O_4}\] to give pyruvic acid is
A. Ethyne
B. Propyne
C. Butyne
D. 2-pentyne
Answer
549.3k+ views
Hint: \[KMn{O_4}\] is a Strong oxidizing agent it oxidizes alkyne to a carboxylic acid for the formation of pyruvic acid in the presence of \[KMn{O_4}\] . We also know that pyruvic acid have 3 carbon atoms in its structural formula given by
\[C{H_3} - \mathop C\limits_{\mathop {||}\limits_O } - \mathop C\limits_{\mathop {||}\limits_O } - OH\]
Complete solution:
First of all we will check the number of carbons present in each of the options given in the question. After that we will find that Pyruvic acid contains three carbon atoms and it is prepared by oxidation of alkynes.
Only propyne has three carbon atoms while ethyne contains 2, butyne contains
4 and 2-pentyne contains 5 carbon atoms.
Pyruvic acid is the simplest alpha keto acid, it contains a carboxylic acid and a ketone functional group.
The molecular formula is \[C{H_3} - \mathop C\limits_{\mathop {||}\limits_O } - \mathop C\limits_{\mathop {||}\limits_O } - OH\]
During strong oxidation with potassium permanganate the alkyne is cleaved into two products.
When \[KMn{O_4}\] act with propyne the \[{C_2}\] and \[{C_3}\] carbon get oxidised to co which can be represented by
\[HC \equiv \mathop {C - C{H_3}}\limits_{Propyne} \xrightarrow{{KMn{O_4}}}H - \begin{array}{*{20}{c}}
{OH} \\
| \\
C \\
| \\
{OH}
\end{array} - \begin{array}{*{20}{c}}
{OH} \\
| \\
C \\
| \\
{OH}
\end{array} - C{H_3}\xrightarrow{{ - 2{H_2}O}}\mathop {C{H_3} - \mathop C\limits_{\mathop {||}\limits_O } - \mathop C\limits_{\mathop {||}\limits_O } - OH}\limits_{Pyruvic{\text{ }}acid} \]
Propyne reacts with \[KMn{O_4}\] in a neutral medium and is oxidized in pyruvic acid.
So, that alkyne will be propyne.
Hence, option (B) is correct.
Note:At normal temperature pyruvic acid is a colorless liquid. It has a pungent smell. Its melting point is ${13.6^0}{\text{ C}}$ and the boiling point is ${165^0}{\text{ C}}$ . It is used as a starting material of biosynthesis of pharmaceuticals.
\[C{H_3} - \mathop C\limits_{\mathop {||}\limits_O } - \mathop C\limits_{\mathop {||}\limits_O } - OH\]
Complete solution:
First of all we will check the number of carbons present in each of the options given in the question. After that we will find that Pyruvic acid contains three carbon atoms and it is prepared by oxidation of alkynes.
Only propyne has three carbon atoms while ethyne contains 2, butyne contains
4 and 2-pentyne contains 5 carbon atoms.
Pyruvic acid is the simplest alpha keto acid, it contains a carboxylic acid and a ketone functional group.
The molecular formula is \[C{H_3} - \mathop C\limits_{\mathop {||}\limits_O } - \mathop C\limits_{\mathop {||}\limits_O } - OH\]
During strong oxidation with potassium permanganate the alkyne is cleaved into two products.
When \[KMn{O_4}\] act with propyne the \[{C_2}\] and \[{C_3}\] carbon get oxidised to co which can be represented by
\[HC \equiv \mathop {C - C{H_3}}\limits_{Propyne} \xrightarrow{{KMn{O_4}}}H - \begin{array}{*{20}{c}}
{OH} \\
| \\
C \\
| \\
{OH}
\end{array} - \begin{array}{*{20}{c}}
{OH} \\
| \\
C \\
| \\
{OH}
\end{array} - C{H_3}\xrightarrow{{ - 2{H_2}O}}\mathop {C{H_3} - \mathop C\limits_{\mathop {||}\limits_O } - \mathop C\limits_{\mathop {||}\limits_O } - OH}\limits_{Pyruvic{\text{ }}acid} \]
Propyne reacts with \[KMn{O_4}\] in a neutral medium and is oxidized in pyruvic acid.
So, that alkyne will be propyne.
Hence, option (B) is correct.
Note:At normal temperature pyruvic acid is a colorless liquid. It has a pungent smell. Its melting point is ${13.6^0}{\text{ C}}$ and the boiling point is ${165^0}{\text{ C}}$ . It is used as a starting material of biosynthesis of pharmaceuticals.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

