Question

The abscissa is 2, the point is $\left( 2,2 \right)$ and $\left( 2,-4 \right)$
If true then enter 1 and if false then enter 0.

Answer 1

Hint:
For a point plotted on the graph, x- coordinate is called abscissa. From the points given in the ordered pair, we will identify the abscissa. We will check the abscissa of every point and then we will write the value zero or one accordingly.

Complete step by step solution:
Given two points are $\left( 2,2 \right)$ and $\left( 2,-4 \right)$.
A point is plotted in a graph using an ordered pair.
For an ordered pair $\left( x,y \right)$, $x$ denotes the x coordinate and $y$ denotes the y-coordinate here.
Here x- coordinate is known as abscissa.
Now consider the points $A\left( 2,2 \right)$ and $D\left( 2,-4 \right)$.
Both points have abscissa equal to 2.
Here we have to answer in such a way that we have to enter 1 when the abscissa of the point 2 and we have to enter 0 when the abscissa of the point is other than 2.
So, for point $A\left( 2,2 \right)$, the answer is 1 as the abscissa of the point is 2 here.
Also, for point $D\left( 2,-4 \right)$, the answer is 1 as the abscissa of the point is 2 here.
Similarly we will check for other points as well.
For $B\left( 5,0 \right)$, the answer is 0.
For point, $C\left( -4,3 \right)$, the answer is 0.
For point, $E\left( 6,3 \right)$, the answer is 0.
For point, $F\left( -4,-3 \right)$, the answer is 0.
For point, $G\left( 5,-3 \right)$, the answer is 0.
For point, $H\left( 5,5 \right)$, the answer is 0.
For point, $I\left( 4,4 \right)$, the answer is 0.

Note:
A point in three dimensional spaces is plotted as an ordered triplet. We have seen that the abscissa is the other name of the x-coordinate of a point and the y-coordinate of a point is known as ordinate. Abscissa denotes the shortest distance of a point from the y axis and ordinate denotes the shortest distance of a point from the x axis.