
How many terms of the A.P. 3, 5, 7, 9…. must be added to get the sum of 120?
Answer
509.7k+ views
Hint:
Find the first term and common difference of the given A.P. Then substitute these values in the formula to find the sum of n terms and thus find the number of terms, n.
Complete step-by-step answer:
A.P. represents arithmetic progression. It is a sequence of numbers such that the difference between the consecutive terms is constant. Difference here means the second minus the first term. Let us consider ‘d’ as the common difference of the arithmetic progress and d is a natural number.
We have been given the A.P.- 3,5,7,9….
where first term, a = 3
common difference, d = 5 – 3 = 2.
The sum of first n terms of an A.P. can be found using the formula,
\[{{S}_{n}}=\dfrac{n}{2}\left[ 2a+(n-1)d \right]\]
where n is the number of terms, which we need to find.
We have been given, \[{{S}_{n}}=120\].
\[\therefore \]Put \[{{S}_{n}}=120\], a = 3 and d = 2.Find the value of n.
\[\begin{align}
& 120=\dfrac{n}{2}\left[ 2\times 3+(n-1)2 \right] \\
& 240=n\left[ 6+2n-2 \right] \\
\end{align}\]
\[\begin{align}
& 240=n\left[ 4+2n \right] \\
& \therefore 240=4n+2{{n}^{2}} \\
& \Rightarrow 2{{n}^{2}}+4n-240=0 \\
\end{align}\]
Divide the entire equation by 2.
\[\therefore {{n}^{2}}+2n-120=0\]
The above expression is similar to the quadratic equation \[a{{x}^{2}}+bx+c=0\].
Thus comparing both equations, we get,
a = 1, b = 2 and c = -120.
Put the values in quadratic formula, \[\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}\].
\[n=\dfrac{-2\pm \sqrt{4-4\times 1\times (-120)}}{2\times 1}=\dfrac{-2\pm
\sqrt{4+480}}{2}=\dfrac{-2\pm 22}{2}\]
\[n=\dfrac{-2+22}{2}\] and \[n=\dfrac{-2-22}{2}=\dfrac{-24}{2}=-12\]
\[\therefore n=\dfrac{20}{2}=10\].
The number of terms cannot be negative, so don’t take = -12.
\[\therefore n=10\]
Thus we got the number of terms as 10.
The number of terms can be added = 10 – 4 = 6 terms.
Note: Arithmetic progression is one of the very important portions to solve the sequence and series. Thus, it’s important that you remember the basic formulae to find the sum and also to get the number of terms in the series.
Find the first term and common difference of the given A.P. Then substitute these values in the formula to find the sum of n terms and thus find the number of terms, n.
Complete step-by-step answer:
A.P. represents arithmetic progression. It is a sequence of numbers such that the difference between the consecutive terms is constant. Difference here means the second minus the first term. Let us consider ‘d’ as the common difference of the arithmetic progress and d is a natural number.
We have been given the A.P.- 3,5,7,9….
where first term, a = 3
common difference, d = 5 – 3 = 2.
The sum of first n terms of an A.P. can be found using the formula,
\[{{S}_{n}}=\dfrac{n}{2}\left[ 2a+(n-1)d \right]\]
where n is the number of terms, which we need to find.
We have been given, \[{{S}_{n}}=120\].
\[\therefore \]Put \[{{S}_{n}}=120\], a = 3 and d = 2.Find the value of n.
\[\begin{align}
& 120=\dfrac{n}{2}\left[ 2\times 3+(n-1)2 \right] \\
& 240=n\left[ 6+2n-2 \right] \\
\end{align}\]
\[\begin{align}
& 240=n\left[ 4+2n \right] \\
& \therefore 240=4n+2{{n}^{2}} \\
& \Rightarrow 2{{n}^{2}}+4n-240=0 \\
\end{align}\]
Divide the entire equation by 2.
\[\therefore {{n}^{2}}+2n-120=0\]
The above expression is similar to the quadratic equation \[a{{x}^{2}}+bx+c=0\].
Thus comparing both equations, we get,
a = 1, b = 2 and c = -120.
Put the values in quadratic formula, \[\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}\].
\[n=\dfrac{-2\pm \sqrt{4-4\times 1\times (-120)}}{2\times 1}=\dfrac{-2\pm
\sqrt{4+480}}{2}=\dfrac{-2\pm 22}{2}\]
\[n=\dfrac{-2+22}{2}\] and \[n=\dfrac{-2-22}{2}=\dfrac{-24}{2}=-12\]
\[\therefore n=\dfrac{20}{2}=10\].
The number of terms cannot be negative, so don’t take = -12.
\[\therefore n=10\]
Thus we got the number of terms as 10.
The number of terms can be added = 10 – 4 = 6 terms.
Note: Arithmetic progression is one of the very important portions to solve the sequence and series. Thus, it’s important that you remember the basic formulae to find the sum and also to get the number of terms in the series.
Recently Updated Pages
What happens to glucose which enters nephron along class 10 biology CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

When the JanmiKudian Act was passed that granted the class 10 social science CBSE

A sector containing an angle of 120 circ is cut off class 10 maths CBSE

The sum of digits of a two digit number is 13 If t-class-10-maths-ICSE

Trending doubts
The shortest day of the year in India

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

What is the missing number in the sequence 259142027 class 10 maths CBSE

