
Taking one light year i equal to \[9.4 \times {10^{15}}m\]and one day is equal to \[86400s\], what will be the speed of light in light year per day if the speed of light in m/s is $3 \times {10^8}m/s$.
Answer
566.4k+ views
Hint:-Here we will use light year and one day in terms of m and second respectively then substitute them in the value of speed of light so that we can get the speed of light in light year per day
Complete step by step solution
The light-year is a unit of distance and is used to measure astronomical distances and is equivalent to about 9.46 trillion kilometres (9.46 x 1012 km) or 5.88 trillion miles (5.88 x 1012 mi).
Since speed of light is $ \Rightarrow 2.75 \times {10^{ - 3}}ly/day$ $3 \times {10^8}\dfrac{m}{s}$.............(1)
So here in the place of m we can substitute the value of the light year as 1m and in second we can substitute days as 1 second.
$\because 1ly = 9.46 \times {10^{15}}m$
So I m will be equal to $\dfrac{{1ly}}{{9.46 \times {{10}^{15}}}} = 1m$
And we have one day is equal to \[86400s\]
So, $\dfrac{{1day}}{{86400}} = s$
Then from equation (1)
speed of light in light year per day is
$ \Rightarrow 3 \times {10^8}\dfrac{{\dfrac{1}{{9.46 \times {{10}^{15}}m}}}}{{\dfrac{{1day}}{{86400}}}}$
$ \Rightarrow 2.75 \times {10^{ - 3}}ly/day$
Note:-The speed of light in vacuum air or in space is a universal physical constant used in many areas of physics. Its exact value is around 299792458 metres per second which is approximately 300000 km/s, or 186000 miles/s. it is generally denoted by c. Speed of light in other medium like glass, water is less than
It was first demonstrated by Ole Christensen Rømer in 1676 that light travels at a finite speed (non-instantaneously) by studying the apparent motion of Jupiter's moon Io.
Complete step by step solution
The light-year is a unit of distance and is used to measure astronomical distances and is equivalent to about 9.46 trillion kilometres (9.46 x 1012 km) or 5.88 trillion miles (5.88 x 1012 mi).
Since speed of light is $ \Rightarrow 2.75 \times {10^{ - 3}}ly/day$ $3 \times {10^8}\dfrac{m}{s}$.............(1)
So here in the place of m we can substitute the value of the light year as 1m and in second we can substitute days as 1 second.
$\because 1ly = 9.46 \times {10^{15}}m$
So I m will be equal to $\dfrac{{1ly}}{{9.46 \times {{10}^{15}}}} = 1m$
And we have one day is equal to \[86400s\]
So, $\dfrac{{1day}}{{86400}} = s$
Then from equation (1)
speed of light in light year per day is
$ \Rightarrow 3 \times {10^8}\dfrac{{\dfrac{1}{{9.46 \times {{10}^{15}}m}}}}{{\dfrac{{1day}}{{86400}}}}$
$ \Rightarrow 2.75 \times {10^{ - 3}}ly/day$
Note:-The speed of light in vacuum air or in space is a universal physical constant used in many areas of physics. Its exact value is around 299792458 metres per second which is approximately 300000 km/s, or 186000 miles/s. it is generally denoted by c. Speed of light in other medium like glass, water is less than
It was first demonstrated by Ole Christensen Rømer in 1676 that light travels at a finite speed (non-instantaneously) by studying the apparent motion of Jupiter's moon Io.
Recently Updated Pages
Master Class 11 Chemistry: Engaging Questions & Answers for Success

Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

