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Take Sarita’s present age to be $y$ years. What was her age $3$ years ago?

Answer
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491.4k+ views
Hint: First, we need to know about the operations of mathematics. And then we will convert the given words to mathematical form, like $3$ years back means it will be represented in mathematics as $ - 3$ from the originally given age and after $3$ years means it will be represented mathematically as $ + 3$ from the originally given age.

Complete step-by-step solution:
Subtraction is the minus of two or more than two numbers or values example $2 - 3 = - 1$ (larger number signs stays constant)
Since as we said the $3$ years back will be expressed mathematically as $ - 3$ and also from the given that we have Sarita’s present age to be $y$ years.
Hence Sarita’s age $3$ years back will be expressed mathematically as $y - 3$ and thus which is the required answer.
Additional information:
Also, we will need to know if the given problem is about after $3$ years means it will be represented mathematically as $ + 3$ from the originally given age and since we have Sarita’s present age to be $y$ years. (Addition is the summing of two or more than two numbers, or values, or variables, and in addition if we sum the two or more numbers a new frame of the number will be found,)
 Therefore, we have found Sarita’s age after $3$ years is $y + 3$.

Note: In words to mathematics, before means subtraction, after means addition, Times means multiplication
 and by means of division.
Since multiplicand refers to the number multiplied. Also, a multiplier refers to the number that multiplies the first number. Have a look at an example; while multiplying $5 \times 7$the number $5$is called the multiplicand and the number $7$is called the multiplier. Hence, we get the time of the given age as $3y$
The process of the inverse of the multiplication method is called division. Like $x \times y = z$ is multiplication thus the division sees as $x = \dfrac{z}{y}$. We usually need to memorize the multiplication tables in childhood so it will help to do mathematics. Hence, we get the age as $\dfrac{y}{3}$