What sum of money will amount to ₹ $ 15972 $ in three years at $ 10\% $ per annum compounded yearly?
Answer
603k+ views
Hint: Use the formula for compound interest. It is a simple formula based question. Since it is given interest is compounded annually we must use the formula for compound interest.
Complete step-by-step answer:
We know that, total amount in compound interest is given by
$ A = P \times {\left( {1 + \dfrac{R}{{100}}} \right)^T} $
Where, $ A $ is amount
$ P $ is principal amount
$ R $ is the rate of interest per annum compounded yearly
$ T $ is time period
Here we have
Amount, $ A = $ ₹ $ 15972 $
Rate per interest, $ R = 10\% $
Time, $ T = 3 $ years.
Now putting all the values in formula.
$ A = P{\left( {1 + \dfrac{R}{{100}}} \right)^T} $
We get,
$ 15972 = P \times {\left( {1 + \dfrac{{10}}{{100}}} \right)^3} $
$ \Rightarrow 15972 = P \times {\left( {1 + \dfrac{1}{{10}}} \right)^3} $
By cross multiplying, we get
$ \Rightarrow 15972 = P \times {\left( {\dfrac{{10 + 1}}{{10}}} \right)^3} $
$ \Rightarrow 157972 = P \times {\left( {\dfrac{{11}}{{10}}} \right)^3} $
$ \Rightarrow 15972 = P \times \dfrac{{1331}}{{1000}} $
$ \Rightarrow P = \dfrac{{15972 \times 1000}}{{1331}} $
$ = \dfrac{{15972000}}{{1331}} $
$ \Rightarrow P = $ ₹ $ 12000 $
Note: You should divide the numerator and denominator into the multiples of prime factors and then cancel out the common factors to simplify the fraction. It would be comparatively easy.
Complete step-by-step answer:
We know that, total amount in compound interest is given by
$ A = P \times {\left( {1 + \dfrac{R}{{100}}} \right)^T} $
Where, $ A $ is amount
$ P $ is principal amount
$ R $ is the rate of interest per annum compounded yearly
$ T $ is time period
Here we have
Amount, $ A = $ ₹ $ 15972 $
Rate per interest, $ R = 10\% $
Time, $ T = 3 $ years.
Now putting all the values in formula.
$ A = P{\left( {1 + \dfrac{R}{{100}}} \right)^T} $
We get,
$ 15972 = P \times {\left( {1 + \dfrac{{10}}{{100}}} \right)^3} $
$ \Rightarrow 15972 = P \times {\left( {1 + \dfrac{1}{{10}}} \right)^3} $
By cross multiplying, we get
$ \Rightarrow 15972 = P \times {\left( {\dfrac{{10 + 1}}{{10}}} \right)^3} $
$ \Rightarrow 157972 = P \times {\left( {\dfrac{{11}}{{10}}} \right)^3} $
$ \Rightarrow 15972 = P \times \dfrac{{1331}}{{1000}} $
$ \Rightarrow P = \dfrac{{15972 \times 1000}}{{1331}} $
$ = \dfrac{{15972000}}{{1331}} $
$ \Rightarrow P = $ ₹ $ 12000 $
Note: You should divide the numerator and denominator into the multiples of prime factors and then cancel out the common factors to simplify the fraction. It would be comparatively easy.
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