
What sum of money will amount to ₹ $ 15972 $ in three years at $ 10\% $ per annum compounded yearly?
Answer
582.3k+ views
Hint: Use the formula for compound interest. It is a simple formula based question. Since it is given interest is compounded annually we must use the formula for compound interest.
Complete step-by-step answer:
We know that, total amount in compound interest is given by
$ A = P \times {\left( {1 + \dfrac{R}{{100}}} \right)^T} $
Where, $ A $ is amount
$ P $ is principal amount
$ R $ is the rate of interest per annum compounded yearly
$ T $ is time period
Here we have
Amount, $ A = $ ₹ $ 15972 $
Rate per interest, $ R = 10\% $
Time, $ T = 3 $ years.
Now putting all the values in formula.
$ A = P{\left( {1 + \dfrac{R}{{100}}} \right)^T} $
We get,
$ 15972 = P \times {\left( {1 + \dfrac{{10}}{{100}}} \right)^3} $
$ \Rightarrow 15972 = P \times {\left( {1 + \dfrac{1}{{10}}} \right)^3} $
By cross multiplying, we get
$ \Rightarrow 15972 = P \times {\left( {\dfrac{{10 + 1}}{{10}}} \right)^3} $
$ \Rightarrow 157972 = P \times {\left( {\dfrac{{11}}{{10}}} \right)^3} $
$ \Rightarrow 15972 = P \times \dfrac{{1331}}{{1000}} $
$ \Rightarrow P = \dfrac{{15972 \times 1000}}{{1331}} $
$ = \dfrac{{15972000}}{{1331}} $
$ \Rightarrow P = $ ₹ $ 12000 $
Note: You should divide the numerator and denominator into the multiples of prime factors and then cancel out the common factors to simplify the fraction. It would be comparatively easy.
Complete step-by-step answer:
We know that, total amount in compound interest is given by
$ A = P \times {\left( {1 + \dfrac{R}{{100}}} \right)^T} $
Where, $ A $ is amount
$ P $ is principal amount
$ R $ is the rate of interest per annum compounded yearly
$ T $ is time period
Here we have
Amount, $ A = $ ₹ $ 15972 $
Rate per interest, $ R = 10\% $
Time, $ T = 3 $ years.
Now putting all the values in formula.
$ A = P{\left( {1 + \dfrac{R}{{100}}} \right)^T} $
We get,
$ 15972 = P \times {\left( {1 + \dfrac{{10}}{{100}}} \right)^3} $
$ \Rightarrow 15972 = P \times {\left( {1 + \dfrac{1}{{10}}} \right)^3} $
By cross multiplying, we get
$ \Rightarrow 15972 = P \times {\left( {\dfrac{{10 + 1}}{{10}}} \right)^3} $
$ \Rightarrow 157972 = P \times {\left( {\dfrac{{11}}{{10}}} \right)^3} $
$ \Rightarrow 15972 = P \times \dfrac{{1331}}{{1000}} $
$ \Rightarrow P = \dfrac{{15972 \times 1000}}{{1331}} $
$ = \dfrac{{15972000}}{{1331}} $
$ \Rightarrow P = $ ₹ $ 12000 $
Note: You should divide the numerator and denominator into the multiples of prime factors and then cancel out the common factors to simplify the fraction. It would be comparatively easy.
Recently Updated Pages
Master Class 8 Social Science: Engaging Questions & Answers for Success

Master Class 8 English: Engaging Questions & Answers for Success

Class 8 Question and Answer - Your Ultimate Solutions Guide

Master Class 8 Maths: Engaging Questions & Answers for Success

Master Class 8 Science: Engaging Questions & Answers for Success

Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Full form of STD, ISD and PCO

Advantages and disadvantages of science

Right to vote is a AFundamental Right BFundamental class 8 social science CBSE

What are the 12 elements of nature class 8 chemistry CBSE

