Question

Sum of \[\dfrac{7}{{12}},\dfrac{{19}}{{12}},\dfrac{8}{{12}}\]is
A). \[\dfrac{{26}}{{12}}\]
B). \[\dfrac{{19}}{{12}}\]
C). \[\dfrac{{27}}{{12}}\]
D). \[\dfrac{{23}}{{12}}\]

Answer 1

Hint: The given question is to add the given numbers, in order to get the total sum of these numbers, here we need to add these terms, by method of addition of fractions. In fraction addition we first need to check for the denominators, if the denominators are the same then we can easily add the numerators.
Formulae Used: By using factorization method, we can make denominators the same for the number of fractions given in the question. Here we have to find the lowest common factor in order to make the denominator the same.

Complete step-by-step solution:
Here to solve the question we need to see the denominators are same or not for all the fractions, and then solve the question accordingly, on solving we get:
\[ \Rightarrow \dfrac{7}{{12}},\dfrac{{19}}{{12}},\dfrac{8}{{12}}\]
Here the denominators are the same in all the fractions.
Now adding these fractions we get:
\[ \Rightarrow \dfrac{7}{{12}} + \dfrac{{19}}{{12}} + \dfrac{8}{{12}} = \dfrac{{7 + 19 + 8}}{{12}} = \dfrac{{34}}{{12}}\]
This is our required answer.

Note: Here to solve the operations like addition and subtraction on fractions, here we need to first make the denominators common and then solve further. To make the denominators the same here we need to find the lowest common factor and then solve further.