Question

What is the sum of angles of a convex polygon whose number of sides is $10$?

Answer 1

Hint- In this question number of sides of convex polygon is given so that, in order to find the sum of angles, we must further subtract $2$ from the number of sides by multiplying it by \[{180^0}\] we will get the answer needed.

Complete step-by-step answer:
Given that the number of convex polygon sides is $10$
As we know the sum of the inner angles of a regular convex polygon $'n'$ sided is given by the formula:

$(n - 2) \times {180^0}$

Where $'n'$ is the number of convex polygons on each side

Here the question is given as $10$

$n = 10$.

Now, we are going to substitute the value of n in the formula above, so we have

\[
   = (10 - 2) \times {180^0} \\
   = 8 \times {180^0} \\
   = {1440^0} \\
 \]

Hence, the sum of angles of a convex polygon is \[{1440^0}\]

Note- A regular polygon is a flat shape, all of whose sides are equal, and all of whose angles are equal. The formula to find the sum of the interior angle calculation is $(n - 2) \times {180^0}$. We take the formula and divide it by the number of sides $(n - 2) \times {180^0} \div n$. to find the value of one interior angle