
Sulphur forms two chlorides ${S_2}C{l_2}$ and $SC{l_2}$ . The equivalent mass of sulphur in $SC{l_2}$ is 16.the equivalent weight of sulphur in ${S_2}C{l_2}$ is?
a.) 8
b.) 16
c.) 64
d.) 32
Answer
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Hint: In order to solve this question first we will define the term equivalent weight of any compound further than with the help of given equivalent mass of sulphur we will calculate the required equivalent weight of sulphur in the given compound.
Equivalent weight: Equivalent weight, in chemistry is the quantity of a substance in a particular reaction that precisely interacts with, or is equal to, the mixture value of, an objectively determined quantity of another substance. Substances react in stoichiometric proportions, or chemically identical, to each other and a common model was adopted. An element's equal mass is its gram atomic weight divided by its valence (combining power).
Complete step by step answer:
Equivalent mass of sulphur in $SC{l_2}$ is 16, which means that 16gm of sulphur is combined with 35.5gm of chlorine.
In ${S_2}C{l_2}$ molecule,
71gm of chlorine is combined with 64gm of sulphur.
Which means by unitary method, 1gm of chlorine will combine with $\dfrac{{64}}{{71}}$gm of sulphur.
Similarly, for finding the finding the equivalent weight of sulphur in ${S_2}C{l_2}$ molecule, we have:
By the unitary method 35.5gm of chlorine will combine with $\dfrac{{64}}{{71}} \times 35.5 = 32$ gm of sulphur.
Hence, the equivalent weight of sulphur in ${S_2}C{l_2}$ molecule is 32 grams
So, the correct answer is “Option D”.
Note: Sulphur chlorides are found to be in mainly three forms as follows:
Disulphur dichloride, ${S_2}C{l_2}$
Sulphur dichloride, $SC{l_2}$
Sulphur tetrachloride, $SC{l_4}$
Disulphur dichloride is having the formula ${S_2}C{l_2}$, and sometimes called sulphur monochloride due to the empirical formula SCl. It is light-amber to yellow-red colour and has an oily liquid appearance.
Sulphur dichloride is the simplest form of the sulphur chloride and it is most common. It is having the formula $SC{l_2}$. The appearance of the Sulphur dichloride is cherry-red liquid.
The inorganic compound Sulphur tetrachloride having the formula is $SC{l_4}$. It is like a white powder in appearance and it can only be obtained as an unstable pale yellow solid while the corresponding fluorine compound $S{F_4}$ is a stable and useful reagent.
Equivalent weight: Equivalent weight, in chemistry is the quantity of a substance in a particular reaction that precisely interacts with, or is equal to, the mixture value of, an objectively determined quantity of another substance. Substances react in stoichiometric proportions, or chemically identical, to each other and a common model was adopted. An element's equal mass is its gram atomic weight divided by its valence (combining power).
Complete step by step answer:
Equivalent mass of sulphur in $SC{l_2}$ is 16, which means that 16gm of sulphur is combined with 35.5gm of chlorine.
In ${S_2}C{l_2}$ molecule,
71gm of chlorine is combined with 64gm of sulphur.
Which means by unitary method, 1gm of chlorine will combine with $\dfrac{{64}}{{71}}$gm of sulphur.
Similarly, for finding the finding the equivalent weight of sulphur in ${S_2}C{l_2}$ molecule, we have:
By the unitary method 35.5gm of chlorine will combine with $\dfrac{{64}}{{71}} \times 35.5 = 32$ gm of sulphur.
Hence, the equivalent weight of sulphur in ${S_2}C{l_2}$ molecule is 32 grams
So, the correct answer is “Option D”.
Note: Sulphur chlorides are found to be in mainly three forms as follows:
Disulphur dichloride, ${S_2}C{l_2}$
Sulphur dichloride, $SC{l_2}$
Sulphur tetrachloride, $SC{l_4}$
Disulphur dichloride is having the formula ${S_2}C{l_2}$, and sometimes called sulphur monochloride due to the empirical formula SCl. It is light-amber to yellow-red colour and has an oily liquid appearance.
Sulphur dichloride is the simplest form of the sulphur chloride and it is most common. It is having the formula $SC{l_2}$. The appearance of the Sulphur dichloride is cherry-red liquid.
The inorganic compound Sulphur tetrachloride having the formula is $SC{l_4}$. It is like a white powder in appearance and it can only be obtained as an unstable pale yellow solid while the corresponding fluorine compound $S{F_4}$ is a stable and useful reagent.
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