
Subtract the following on the number line:
A). 9 from 4
B). 9 from -4
C). -8 from3
Answer
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Hint: In this question, we have to find the values of the given question by solving them on a number line. So, we will use the number line method to get the solution. As we know, if we have to subtract a from b, the mathematical meaning is $b-a$ . Thus, in this problem, we will first draw the number line with 1 unit each. After that, we will mark ‘b’ on the number line and then move a to the left of the b, to get the required solution for the problem.
Complete step-by-step solution:
According to the problem, we have to find the value of each option.
Thus, we will use the number line and the basic mathematical rules.
A). 9 from 4
So, we know that if the statement is in the form $a\text{ from }b$ , then its mathematical term is $b-a$ . thus, here $b=4$ and $a=9$ , which implies we have to find $4-9$ .
Now, we will first draw the number line of each unit, that is
Now, we will go $a$ units left from $b$ , which is 9 units left from the number 4, we get
As we move towards the left, that is we cross number 3, 2, 1, 0, … -4, thus the required answer for the given statement is -5.
B). 9 from -4
So, we know that if the statement is in the form $a\text{ from }b$ , then its mathematical term is $b-a$ . thus, here $b=-4$ and $a=9$ , which implies we have to find $-4-9$ .
Now, we will first draw the number line of each unit, that is
Now, we will go $a$ units left from $b$ , which is 9 units left from the number -4, we get
As we move towards the left, that is we cross number -12,…, -6,-5 , thus the required answer for the given statement is -13.
C). -8 from 3
So, we know that if the statement is in the form $a\text{ from }b$ , then its mathematical term is $b-a$ . thus, here $b=3$ and $a=-8$ , which implies we have to find $3-\left( -8 \right)=3+8$
Now, we will first draw the number line of each unit, that is
Now, we will go $a$ units right from $b$ , which is 8 units right from the number 3, we get
As we move towards right, that is we cross number 4, 5, 6, …, 10 thus the required answer for the given statement is 11.
Therefore, we get the required solution for all the three parts.
Note: While solving this problem, do not forget to draw the number line with 1 unit each. Also, do not confuse writing the statement $a\text{ from }b$, it is equal to $b-a$ and not $a-b$ . Always remember that when we subtract, we will go to the left of the number and when we add, we will go right of the number.
Complete step-by-step solution:
According to the problem, we have to find the value of each option.
Thus, we will use the number line and the basic mathematical rules.
A). 9 from 4
So, we know that if the statement is in the form $a\text{ from }b$ , then its mathematical term is $b-a$ . thus, here $b=4$ and $a=9$ , which implies we have to find $4-9$ .
Now, we will first draw the number line of each unit, that is

Now, we will go $a$ units left from $b$ , which is 9 units left from the number 4, we get

As we move towards the left, that is we cross number 3, 2, 1, 0, … -4, thus the required answer for the given statement is -5.
B). 9 from -4
So, we know that if the statement is in the form $a\text{ from }b$ , then its mathematical term is $b-a$ . thus, here $b=-4$ and $a=9$ , which implies we have to find $-4-9$ .
Now, we will first draw the number line of each unit, that is

Now, we will go $a$ units left from $b$ , which is 9 units left from the number -4, we get

As we move towards the left, that is we cross number -12,…, -6,-5 , thus the required answer for the given statement is -13.
C). -8 from 3
So, we know that if the statement is in the form $a\text{ from }b$ , then its mathematical term is $b-a$ . thus, here $b=3$ and $a=-8$ , which implies we have to find $3-\left( -8 \right)=3+8$
Now, we will first draw the number line of each unit, that is

Now, we will go $a$ units right from $b$ , which is 8 units right from the number 3, we get

As we move towards right, that is we cross number 4, 5, 6, …, 10 thus the required answer for the given statement is 11.
Therefore, we get the required solution for all the three parts.
Note: While solving this problem, do not forget to draw the number line with 1 unit each. Also, do not confuse writing the statement $a\text{ from }b$, it is equal to $b-a$ and not $a-b$ . Always remember that when we subtract, we will go to the left of the number and when we add, we will go right of the number.
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