Subtract 94m and 12cm from 100m.
Last updated date: 17th Mar 2023
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Answer
304.8k+ views
Hint: To solve this problem we need to have basic knowledge on the concept of unit and measures and we need to know the unit conversion as we have to convert the given units to single units.
Complete step-by-step answer:
Given units are 94m, 12cm and 100m,
We know that to subtract any values they all should be of the same unit.
But here 12 is in centimetres while others are in metres.
Let us convert centimetres to metres.
We know that,
1metre=100centimetres
Then
12cm = 0.12m
Now let us subtract the values as all given term are in same units
$
\Rightarrow 100m - 94m - 0.12m \\
\Rightarrow 100m - (94 - 0.12)m \\
\Rightarrow 5.88m \\
$
Therefore the value is 5.88m
Note: In this problem we have to subtract the given values. Generally in this type of problem we will subtract the value normally if units are not mentioned or all units are the same. Any operation is possible only when all are of the same units. If the values do not belong to the same unit we have to convert the values into the same units and then we have to apply the operations. The above problem has been done in the same procedure.
Complete step-by-step answer:
Given units are 94m, 12cm and 100m,
We know that to subtract any values they all should be of the same unit.
But here 12 is in centimetres while others are in metres.
Let us convert centimetres to metres.
We know that,
1metre=100centimetres
Then
12cm = 0.12m
Now let us subtract the values as all given term are in same units
$
\Rightarrow 100m - 94m - 0.12m \\
\Rightarrow 100m - (94 - 0.12)m \\
\Rightarrow 5.88m \\
$
Therefore the value is 5.88m
Note: In this problem we have to subtract the given values. Generally in this type of problem we will subtract the value normally if units are not mentioned or all units are the same. Any operation is possible only when all are of the same units. If the values do not belong to the same unit we have to convert the values into the same units and then we have to apply the operations. The above problem has been done in the same procedure.
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