Question

State true or false.
Standard ambient temperature and pressure (STP) mean ${{298}}{{.15K}}$ and 1 bar ${{(1}}{{{0}}^{{5}}}{{Pa)}}$ pressure.
A.True
B.False

Answer 1

Hint:Standard ambient temperature and pressure (SATP) is another form of STP (Standard temperature and pressure) conditions. Standard temperature and pressure are defined by the International Union of pure and applied chemistry (IUPAC). There are various forms of standard conditions. Room temperature is not the standard temperature.

Complete step by step answer:
The standard ambient temperature is $298.15K$ and standard pressure is $1bar$.
SATP is a reference standard condition.
According to SATP, the standard ambient temperature is at ${25^o}C$.
To convert degree Celsius to kelvin, we have to add ${273^o}C$ to the temperature in degree Celsius.
Thus $25 + 273 = 298K$
Therefore at SATP, standard ambient temperature is $298.15K$ and standard pressure is $1bar({10^5}Pa)$
At STP conditions, the standard temperature is taken as ${0^o}C$ or $273K$.
The standard pressure is $1atm$.
$1mol$ of gas at STP occupies $22.4L$.
SATP conditions are taken as a more convenient reference point than STP conditions.
STP conditions are used in calculations of the chemical and physical processes.
There are various definitions of standard temperature and pressure.
NTP is another standard condition used. NTP is the normal temperature and pressure.
At NTP, the conditions are ${20^o}C(293.15K)$ and $1atm$
The international standard atmosphere (ISA) is another standard reference used.
At ISA conditions, the temperature is ${15^o}C$ and pressure is $1atm$.
Thus the answer is an option (A). Standard ambient temperature indeed is $298.15K$ and standard pressure is $1bar$.


Note:
STP (Standard temperature and pressure) is $273.15K$ and $1atm$. SATP (Standard ambient temperature and pressure) is $298.15K$ and $1bar$. STP conditions are the old reference used. The new standard reference used is the SATP where the standard ambient temperature is $298.15K$ and standard pressure is $1bar$.