
State the lens formula and write it mathematically.
Answer
556.5k+ views
Hint: To solve the problem we have to know what the lens is. We know that the lens is a transparent refracting medium bounded by either two spherical surfaces or one surface spherical and another surface plane. We know that lenses are of two kinds. One is convex or convergent and the other one is concave or divergent. We can say, A plane surface can be treated as a spherical surface of infinite radius of curvature.
Complete answer:
We know that, the equation relating the distance of object which is u, the distance of image which is v, and the focal length of a lens is called lens formula. It is the same for both concave and convex lenses. Now, the mathematical formula is,
\[\dfrac{1}{v} - \dfrac{1}{u} = \dfrac{1}{f}\]
Note:We can get confused between the signs of the elements. We know that, in numerical the known values are substituted with their proper sign and then the unknown quantity is obtained with its proper sign. We know that, according to the sign convention for the convex lens, u is always negative, f is always positive, v is positive for the real image and v is negative for virtual image. But for a concave lens we know that, u, v and f all are negative. And then the numerical value of u is always greater than v. from this formula we can also get to know about linear magnification. We denote this linear magnification by m.
Complete answer:
We know that, the equation relating the distance of object which is u, the distance of image which is v, and the focal length of a lens is called lens formula. It is the same for both concave and convex lenses. Now, the mathematical formula is,
\[\dfrac{1}{v} - \dfrac{1}{u} = \dfrac{1}{f}\]
Note:We can get confused between the signs of the elements. We know that, in numerical the known values are substituted with their proper sign and then the unknown quantity is obtained with its proper sign. We know that, according to the sign convention for the convex lens, u is always negative, f is always positive, v is positive for the real image and v is negative for virtual image. But for a concave lens we know that, u, v and f all are negative. And then the numerical value of u is always greater than v. from this formula we can also get to know about linear magnification. We denote this linear magnification by m.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

Give 10 examples of unisexual and bisexual flowers

