Question

Standard molar enthalpy of formation of $C{O_2}$ is equal to:
 A.Zero
 B.The standard molar enthalpy of combustion of gaseous carbon
 C.The sum of standard molar enthalpies of formation of $CO$ and ${O_2}$
 D.The standard molar enthalpy of combustion of carbon (graphite)

Answer 1

Hint: As we probably are aware all responses bring about the arrangement of items from the reactants. Of the multitude of responses that happen, some retain energy while different outcomes in the advancement of energy. Consequently, we generally experience an adjustment of enthalpy at whatever point a response happens. This enthalpy change is portrayed as the enthalpy of response.

Complete answer:
We will manage a couple of other enthalpy changes like enthalpy of development, enthalpy of bond separation and enthalpy of ignition. Standard enthalpy of development is characterized as the enthalpy change when one mole of a compound is framed from its components in their most steady condition of collection.
Standard molar warmth enthalpy $\left( {{H^\circ }} \right)$ of a compound is equivalent to its standard warmth of development from most stable conditions of starting parts.
Subsequently, standard molar enthalpy of arrangement of $C{O_2}$ is equivalent to the standard molar enthalpy of ignition of carbon (graphite).
${C_{\left( g \right)}} + {O_{2\left( g \right)}} \to C{O_{2\left( g \right)}}$
The above response can be viewed as the response for the ignition of carbon (graphite). Same response can likewise be viewed as the response for the arrangement of carbon dioxide.

Note:
We have to know that, standard enthalpy of ignition is characterized as the enthalpy change when one mole of a compound is totally scorched in oxygen with every one of the reactants and items in their standard state under standard conditions.