
What is the square root of \[24\] / square root of \[6\] ?
Answer
476.1k+ views
Hint: According to the question; we have to find the value of the square root of \[24\] / square root of \[6\] i.e., \[\dfrac{{\sqrt {24} }}{{\sqrt 6 }}\] . In order to solve this question, first we will use the property given by \[\dfrac{{\sqrt x }}{{\sqrt y }} = \sqrt {\dfrac{x}{y}} \] and write the given term as \[\sqrt {\dfrac{{24}}{6}} \] . Then we will rewrite the numbers as the product of their prime factors. After that we will cancel the common factors from the numerator and denominator and find the square root of the obtained value.Hence, we will get the required value of the given expression.
Complete step by step answer:
According to the question we have to find the value of is the square root of \[24\] / square root of \[6\] i.e., we have to simplify the value of \[\dfrac{{\sqrt {24} }}{{\sqrt 6 }}\]. Now we know that
\[\dfrac{{\sqrt x }}{{\sqrt y }} = \sqrt {\dfrac{x}{y}} \]
According to the question,
\[x = 24\] and \[y = 6\]
Therefore, we can write
\[\dfrac{{\sqrt {24} }}{{\sqrt 6 }} = \sqrt {\dfrac{{24}}{6}} {\text{ }} - - - \left( i \right)\]
Now we will rewrite \[24\] and \[6\] as the product of their prime factors.
Therefore, we have
\[24 = 2 \times 2 \times 2 \times 3\]
And \[6 = 2 \times 3\]
Now on substituting the values in the equation \[\left( i \right)\] we have
\[\dfrac{{\sqrt {24} }}{{\sqrt 6 }} = \sqrt {\dfrac{{24}}{6}} = \sqrt {\dfrac{{2 \times 2 \times 2 \times 3}}{{2 \times 3}}} \]
Here we can see the numerator and denominator have the common factor as \[2 \times 3\].
So, on cancelling the common factor, we get
\[ \Rightarrow \dfrac{{\sqrt {24} }}{{\sqrt 6 }} = \sqrt {\dfrac{{2 \times 2}}{1}} \]
On solving, we get
\[ \Rightarrow \dfrac{{\sqrt {24} }}{{\sqrt 6 }} = \sqrt 4 \]
Now we know, \[\sqrt 4 = \pm 2\]
Therefore, we have
\[ \therefore \dfrac{{\sqrt {24} }}{{\sqrt 6 }} = \pm 2\]
Hence, the value of \[\dfrac{{\sqrt {24} }}{{\sqrt 6 }}\] is \[ \pm 2\].
Note: We have used the term “prime factors” in the solution. So, a prime factor is a factor that is a prime number. Also note that to simplify the terms inside the radicals, try to factor them to find at least one term that is a perfect square. Also keep in mind when a square root is found we must add the plus-or-minus sign because we have \[{\left( 2 \right)^2} = 4\] and \[{\left( { - 2} \right)^2} = 4\].
Complete step by step answer:
According to the question we have to find the value of is the square root of \[24\] / square root of \[6\] i.e., we have to simplify the value of \[\dfrac{{\sqrt {24} }}{{\sqrt 6 }}\]. Now we know that
\[\dfrac{{\sqrt x }}{{\sqrt y }} = \sqrt {\dfrac{x}{y}} \]
According to the question,
\[x = 24\] and \[y = 6\]
Therefore, we can write
\[\dfrac{{\sqrt {24} }}{{\sqrt 6 }} = \sqrt {\dfrac{{24}}{6}} {\text{ }} - - - \left( i \right)\]
Now we will rewrite \[24\] and \[6\] as the product of their prime factors.
Therefore, we have
\[24 = 2 \times 2 \times 2 \times 3\]
And \[6 = 2 \times 3\]
Now on substituting the values in the equation \[\left( i \right)\] we have
\[\dfrac{{\sqrt {24} }}{{\sqrt 6 }} = \sqrt {\dfrac{{24}}{6}} = \sqrt {\dfrac{{2 \times 2 \times 2 \times 3}}{{2 \times 3}}} \]
Here we can see the numerator and denominator have the common factor as \[2 \times 3\].
So, on cancelling the common factor, we get
\[ \Rightarrow \dfrac{{\sqrt {24} }}{{\sqrt 6 }} = \sqrt {\dfrac{{2 \times 2}}{1}} \]
On solving, we get
\[ \Rightarrow \dfrac{{\sqrt {24} }}{{\sqrt 6 }} = \sqrt 4 \]
Now we know, \[\sqrt 4 = \pm 2\]
Therefore, we have
\[ \therefore \dfrac{{\sqrt {24} }}{{\sqrt 6 }} = \pm 2\]
Hence, the value of \[\dfrac{{\sqrt {24} }}{{\sqrt 6 }}\] is \[ \pm 2\].
Note: We have used the term “prime factors” in the solution. So, a prime factor is a factor that is a prime number. Also note that to simplify the terms inside the radicals, try to factor them to find at least one term that is a perfect square. Also keep in mind when a square root is found we must add the plus-or-minus sign because we have \[{\left( 2 \right)^2} = 4\] and \[{\left( { - 2} \right)^2} = 4\].
Recently Updated Pages
Master Class 8 Social Science: Engaging Questions & Answers for Success

Master Class 8 Maths: Engaging Questions & Answers for Success

Master Class 8 Science: Engaging Questions & Answers for Success

Class 8 Question and Answer - Your Ultimate Solutions Guide

Master Class 8 English: Engaging Questions & Answers for Success

Why are manures considered better than fertilizers class 11 biology CBSE

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Full form of STD, ISD and PCO

Right to vote is a AFundamental Right BFundamental class 8 social science CBSE

What is the difference between rai and mustard see class 8 biology CBSE

Summary of the poem Where the Mind is Without Fear class 8 english CBSE

