
How many spherical bullets can be made out of a solid cube of lead whose edge measures 44cm, each bullet being 4cm in diameter.
Answer
579.3k+ views
Hint:
Here we need to find the number of spherical bullets that can be made out of a cube of lead. For that, we will first assume the number of spherical bullets to be any variable $n$ and then we will find the volume of spherical bullet having diameter 4cm and then we will multiply the value of one spherical bullet by $n$ to calculate the volume of total number of spherical bullets. Then we will equate the value of the volume of $n$ number of spherical bullets with the volume of the cube of sides $44cm$. After equating the value, we will get the number of spherical bullets that can be made out of a solid cube of lead.
Complete step by step solution:
Let the number of spherical bullets that can be made out of a $44cm$ cube of lead be $n$
Now, let’s find the value of volume of spherical bullets of diameter 4cm and of radius 2cm.
Volume of spherical bullets $=\dfrac{4}{3}\pi {{r}^{3}}$
Now, putting the value of the radius of spherical bullets.
Volume of spherical bullets $=\dfrac{4}{3}\pi {{2}^{3}}$
Simplifying the equation further, we get
$=\dfrac{4}{3}\pi \times 8c{{m}^{3}}$
Now putting the value of pi.
$=\dfrac{4}{3}\times \dfrac{22}{7}\times 8c{{m}^{3}}$
We will multiply the terms now.
$=33.52c{{m}^{3}}$
So to calculate the volume of n number of spherical bullets of radius $2cm$ we will multiply it with n.
Volume of number of spherical bullets$=n\times 33.52c{{m}^{3}}$ …………..$\left( 1 \right)$
Now, calculate the value of volume of cube of sides $44cm$ $={{\left( 44cm \right)}^{3}}$
$=85184c{{m}^{3}}$ ……………..$\left( 2 \right)$
Now, equating equation $\left( 1 \right)$ with equation $\left( 2 \right)$ we get;
$85184c{{m}^{3}}=n\times 33.52c{{m}^{3}}$
Now, dividing 85184 by 33.52 we get;
$\Rightarrow n=\dfrac{85184c{{m}^{3}}}{33.52c{{m}^{3}}}$
$=2541.288\approx 2541$
So the required number of spherical bullets that can be made out of a cube of metal is 2541.
Note:
Since we have used volume of a cube, where volume is the measurement of space available in a particular object in cubic units.
We can solve this question by using formula i.e.
$\text{number of spherical bullets formed}=\dfrac{\text{volume of cube}}{\text{volume of one spherical bullet}}$
Here we need to find the number of spherical bullets that can be made out of a cube of lead. For that, we will first assume the number of spherical bullets to be any variable $n$ and then we will find the volume of spherical bullet having diameter 4cm and then we will multiply the value of one spherical bullet by $n$ to calculate the volume of total number of spherical bullets. Then we will equate the value of the volume of $n$ number of spherical bullets with the volume of the cube of sides $44cm$. After equating the value, we will get the number of spherical bullets that can be made out of a solid cube of lead.
Complete step by step solution:
Let the number of spherical bullets that can be made out of a $44cm$ cube of lead be $n$
Now, let’s find the value of volume of spherical bullets of diameter 4cm and of radius 2cm.
Volume of spherical bullets $=\dfrac{4}{3}\pi {{r}^{3}}$
Now, putting the value of the radius of spherical bullets.
Volume of spherical bullets $=\dfrac{4}{3}\pi {{2}^{3}}$
Simplifying the equation further, we get
$=\dfrac{4}{3}\pi \times 8c{{m}^{3}}$
Now putting the value of pi.
$=\dfrac{4}{3}\times \dfrac{22}{7}\times 8c{{m}^{3}}$
We will multiply the terms now.
$=33.52c{{m}^{3}}$
So to calculate the volume of n number of spherical bullets of radius $2cm$ we will multiply it with n.
Volume of number of spherical bullets$=n\times 33.52c{{m}^{3}}$ …………..$\left( 1 \right)$
Now, calculate the value of volume of cube of sides $44cm$ $={{\left( 44cm \right)}^{3}}$
$=85184c{{m}^{3}}$ ……………..$\left( 2 \right)$
Now, equating equation $\left( 1 \right)$ with equation $\left( 2 \right)$ we get;
$85184c{{m}^{3}}=n\times 33.52c{{m}^{3}}$
Now, dividing 85184 by 33.52 we get;
$\Rightarrow n=\dfrac{85184c{{m}^{3}}}{33.52c{{m}^{3}}}$
$=2541.288\approx 2541$
So the required number of spherical bullets that can be made out of a cube of metal is 2541.
Note:
Since we have used volume of a cube, where volume is the measurement of space available in a particular object in cubic units.
We can solve this question by using formula i.e.
$\text{number of spherical bullets formed}=\dfrac{\text{volume of cube}}{\text{volume of one spherical bullet}}$
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
What is the median of the first 10 natural numbers class 10 maths CBSE

Which women's tennis player has 24 Grand Slam singles titles?

Who is the Brand Ambassador of Incredible India?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

A moving boat is observed from the top of a 150 m high class 10 maths CBSE

