
How do you solve this system of equations: \[-6x+6y=-12\] and \[-10x+9y=-17\]?
Answer
552k+ views
Hint: This question is from the topic of algebra. In this question, we will first make the equation \[-6x+6y=-12\] in simpler form. After that, we will solve both the equations and find out the value of x and y. We will use a substitution method to solve the further process of the solution of this question. We will take the value of x from the equation \[-6x+6y=-12\] and the value of x as in the equation \[-10x+9y=-17\]. After solving them, we will get our solution.
Complete step by step solution:
Let us solve this question.
In this question, we have to solve the system of equations. The equations are \[-6x+6y=-12\] and \[-10x+9y=-17\].
On dividing 6 to both sides of the equation \[-6x+6y=-12\] , we can write that equation as
\[\dfrac{-6x+6y}{6}=\dfrac{-12}{6}\]
We can write the above equation as
\[\Rightarrow -x+y=-2\]
The above equation can also be written as
\[\Rightarrow y=-2+x\]
Putting this value of y in the equation \[-10x+9y=-17\], we get
\[-10x+9\left( -2+x \right)=-17\]
The above equation can also be written as
\[\Rightarrow -10x-18+9x=-17\]
The above equation can also be written as
\[\Rightarrow -10x+9x=-17+18\]
The above equation can also be written as
\[\Rightarrow -x=1\]
The above equation can also be written as
\[\Rightarrow x=-1\]
Now, we will put this value of x as -1 in the equation \[-6x+6y=-12\], we will get
\[-6\left( -1 \right)+6y=-12\]
The above equation can also be written as
\[\Rightarrow 6+6y=-12\]
The above equation can also be written as
\[\Rightarrow y=\dfrac{-12-6}{6}=\dfrac{-18}{6}=-3\]
Hence, we get that the solutions to the system of equations are x=-1 and y=-3.
Note: As we can see that this question is from the topic of algebra. So, we should have a better knowledge in that topic. We have used a substitution method to solve this question. Always remember that in the substitution method, the value of one variable from one equation is substituted in that equation.
Complete step by step solution:
Let us solve this question.
In this question, we have to solve the system of equations. The equations are \[-6x+6y=-12\] and \[-10x+9y=-17\].
On dividing 6 to both sides of the equation \[-6x+6y=-12\] , we can write that equation as
\[\dfrac{-6x+6y}{6}=\dfrac{-12}{6}\]
We can write the above equation as
\[\Rightarrow -x+y=-2\]
The above equation can also be written as
\[\Rightarrow y=-2+x\]
Putting this value of y in the equation \[-10x+9y=-17\], we get
\[-10x+9\left( -2+x \right)=-17\]
The above equation can also be written as
\[\Rightarrow -10x-18+9x=-17\]
The above equation can also be written as
\[\Rightarrow -10x+9x=-17+18\]
The above equation can also be written as
\[\Rightarrow -x=1\]
The above equation can also be written as
\[\Rightarrow x=-1\]
Now, we will put this value of x as -1 in the equation \[-6x+6y=-12\], we will get
\[-6\left( -1 \right)+6y=-12\]
The above equation can also be written as
\[\Rightarrow 6+6y=-12\]
The above equation can also be written as
\[\Rightarrow y=\dfrac{-12-6}{6}=\dfrac{-18}{6}=-3\]
Hence, we get that the solutions to the system of equations are x=-1 and y=-3.
Note: As we can see that this question is from the topic of algebra. So, we should have a better knowledge in that topic. We have used a substitution method to solve this question. Always remember that in the substitution method, the value of one variable from one equation is substituted in that equation.
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