
Solve the pair of linear equations by the substitution method.
$s - t = 0$
$\dfrac{s}{3} + \dfrac{t}{2} = 5$
Answer
593.1k+ views
Hint – In this question take out one variable in terms of other variable from any of the two given equations and then substitute it in other equation, this helps formulation of an equation which is solemnly in one variable, solve it to get the variable, then use this value obtained to get other variable.
Complete step-by-step answer:
Given linear equations are
$s - t = 0$..................... (1)
$\dfrac{s}{3} + \dfrac{t}{2} = 5$................... (2)
Now we have to solve this linear equation by substitution method therefore,
From equation (1) we have,
$ \Rightarrow s = t$................. (3)
Now substitute this value in equation (2) we have,
$ \Rightarrow \dfrac{t}{3} + \dfrac{t}{2} = 5$
Now simplify this equation we have,
$ \Rightarrow t\left( {\dfrac{{2 + 3}}{6}} \right) = 5$
$ \Rightarrow t\left( {\dfrac{5}{6}} \right) = 5$
$ \Rightarrow t = 6$
Now from equation (3) we have,
$ \Rightarrow s = t = 6$
So (s, t) = (6, 6)
Hence this is the required solution for the given pair of linear equations.
Note – This question primarily focuses on solving by method of substitution but however there can be another method to solve problems involving two linear equations in two variables. It is elimination, in this method the coefficients of a specific variable of both the equations are made the same and then eliminated using basic operations of addition or subtraction. The other variable which is non-eliminated is taken out. The eliminated variable can be taken out using this variable obtained.
Complete step-by-step answer:
Given linear equations are
$s - t = 0$..................... (1)
$\dfrac{s}{3} + \dfrac{t}{2} = 5$................... (2)
Now we have to solve this linear equation by substitution method therefore,
From equation (1) we have,
$ \Rightarrow s = t$................. (3)
Now substitute this value in equation (2) we have,
$ \Rightarrow \dfrac{t}{3} + \dfrac{t}{2} = 5$
Now simplify this equation we have,
$ \Rightarrow t\left( {\dfrac{{2 + 3}}{6}} \right) = 5$
$ \Rightarrow t\left( {\dfrac{5}{6}} \right) = 5$
$ \Rightarrow t = 6$
Now from equation (3) we have,
$ \Rightarrow s = t = 6$
So (s, t) = (6, 6)
Hence this is the required solution for the given pair of linear equations.
Note – This question primarily focuses on solving by method of substitution but however there can be another method to solve problems involving two linear equations in two variables. It is elimination, in this method the coefficients of a specific variable of both the equations are made the same and then eliminated using basic operations of addition or subtraction. The other variable which is non-eliminated is taken out. The eliminated variable can be taken out using this variable obtained.
Recently Updated Pages
Two men on either side of the cliff 90m height observe class 10 maths CBSE

What happens to glucose which enters nephron along class 10 biology CBSE

Cutting of the Chinese melon means A The business and class 10 social science CBSE

Write a dialogue with at least ten utterances between class 10 english CBSE

Show an aquatic food chain using the following organisms class 10 biology CBSE

A circle is inscribed in an equilateral triangle and class 10 maths CBSE

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Which of the following does not have a fundamental class 10 physics CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

