Question

How do you solve the linear equation $j - \left( { - 17} \right) = 36$?

Answer 1

Hint: Given a linear equation is in one variable which is $j$. We know that the standard form of linear equation in one variable is given by $ax + b = 0$, where the value of the coefficient of the $x$ term is not equal to zero. That is $a \ne 0$, $b$ may or may not be zero. Here we find the solution of the equation by rearranging the like terms together.

Complete step by step solution:
The given linear equation in one variable is given by $j - \left( { - 17} \right) = 36$.
Now consider the given linear equation in one variable, as shown below:
$ \Rightarrow j - \left( { - 17} \right) = 36$
The next step is to simplify the left hand side of the equation by multiplying the negative sign outside the integer -17 with -1, and hence the result would be +17, as shown below:
$ \Rightarrow j + 17 = 36$
Now group the constants to the right hand side of the above equation, and the variable $j$ term on the left hand side of the above equation as shown below. That is transferring the constant 17 to the right hand side of the above equation as shown below:
$ \Rightarrow j = 36 - 17$
$ \Rightarrow j = 19$
Hence the value of the variable $j$ is equal to 19.
The solution of the given linear equation $j - \left( { - 17} \right) = 36$ is equal to 19.

Note: Please note that instead of grouping like terms and the unlike terms together we can actually group all the terms on one side of the linear equation which is the similar form of the standard linear equation $ax + b = 0$, and then divide the equation with $a$, and then moving the constant to the other side which brings the solution to $x = \dfrac{{ - b}}{a}$.