
Solve the given quadratic equation for x:-
\[{{x}^{2}}-7x-18=0\]
Answer
616.5k+ views
- Hint: In this question, we are asked to solve the given quadratic equation which means that we have to find the roots of this given quadratic equation and that can be done by using the quadratic formula which is as follows
\[roots=\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}\]
(For a quadratic equation \[a{{x}^{2}}+bx+c=0\])
Complete step-by-step solution -
As mentioned in the question, we have to find the roots of the given quadratic equation.
Now the quadratic equation is as follows
\[{{x}^{2}}-7x-18=0\]
Now, on using the quadratic formula, we get the following result
\[\begin{align}
& \left( roots=\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a} \right) \\
& \Rightarrow {{x}^{2}}-7x-18=0 \\
& \Rightarrow x=\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a} \\
& \Rightarrow x=\dfrac{-(-7)\pm \sqrt{{{(-7)}^{2}}-4\times 1\times -18}}{2\times 1} \\
& \Rightarrow x=\dfrac{7\pm \sqrt{49+72}}{2} \\
& \Rightarrow x=\dfrac{7\pm \sqrt{121}}{2} \\
& \Rightarrow x=\dfrac{7\pm 11}{2} \\
& \Rightarrow x=\dfrac{7+11}{2},\dfrac{7-11}{2} \\
& \Rightarrow x=\dfrac{18}{2},\dfrac{-4}{2} \\
& \Rightarrow x=9,-2 \\
\end{align}\]
Hence, the roots of the given quadratic equation are 9 and -2.
Note:- Two other methods with which we can solve a quadratic equation are as follows
Splitting the middle term
Completing the square
Both of these methods can be used to solve a quadratic equation and hence we can get the same solution by using them instead of the quadratic formula.
\[roots=\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a}\]
(For a quadratic equation \[a{{x}^{2}}+bx+c=0\])
Complete step-by-step solution -
As mentioned in the question, we have to find the roots of the given quadratic equation.
Now the quadratic equation is as follows
\[{{x}^{2}}-7x-18=0\]
Now, on using the quadratic formula, we get the following result
\[\begin{align}
& \left( roots=\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a} \right) \\
& \Rightarrow {{x}^{2}}-7x-18=0 \\
& \Rightarrow x=\dfrac{-b\pm \sqrt{{{b}^{2}}-4ac}}{2a} \\
& \Rightarrow x=\dfrac{-(-7)\pm \sqrt{{{(-7)}^{2}}-4\times 1\times -18}}{2\times 1} \\
& \Rightarrow x=\dfrac{7\pm \sqrt{49+72}}{2} \\
& \Rightarrow x=\dfrac{7\pm \sqrt{121}}{2} \\
& \Rightarrow x=\dfrac{7\pm 11}{2} \\
& \Rightarrow x=\dfrac{7+11}{2},\dfrac{7-11}{2} \\
& \Rightarrow x=\dfrac{18}{2},\dfrac{-4}{2} \\
& \Rightarrow x=9,-2 \\
\end{align}\]
Hence, the roots of the given quadratic equation are 9 and -2.
Note:- Two other methods with which we can solve a quadratic equation are as follows
Splitting the middle term
Completing the square
Both of these methods can be used to solve a quadratic equation and hence we can get the same solution by using them instead of the quadratic formula.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Explain zero factorial class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

What steps did the French revolutionaries take to create class 11 social science CBSE

The transition element that has lowest enthalpy of class 11 chemistry CBSE

Can anyone list 10 advantages and disadvantages of friction

