
Solve the given linear equation for x: \[4x+5=3x+19\].
Answer
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- Hint: Here the given problem is \[4x+5=3x+19\] .We have to find the value of x by equating and moving the terms from left hand side to right hand side. Moving the common terms to one side and solving.
Complete step-by-step solution -
Moving the x terms to the left hand side and remaining numerical to right hand side and then performing the mathematical operations.
The given problem is \[4x+5=3x+19\] .
Considering L.H.S as \[4x+5\] and R.H.S as \[3x+19\].
Now moving the x terms to the left hand side and remaining numerical to the right hand side. The equation now appears as \[4x-3x=19-5\]
Now x is taken as common in the left hand side, the equation now appears as
\[x\left( 4-3 \right)=19-5\]
Adding all the terms in the right hand side, The equation now appears as \[x=14\] .
Therefore, the value of x is 14.
Note: This is a direct problem where the value of x can be found by moving the terms from L.H.S to R.H.S and performing mathematical expressions. To check placing the value of x in the above equation gives L.H.S = R.H.S. In questions as above the only possible mistake that a student can make is either in the calculation part or a sign error, so be careful about the two points where the error can be made.
Complete step-by-step solution -
Moving the x terms to the left hand side and remaining numerical to right hand side and then performing the mathematical operations.
The given problem is \[4x+5=3x+19\] .
Considering L.H.S as \[4x+5\] and R.H.S as \[3x+19\].
Now moving the x terms to the left hand side and remaining numerical to the right hand side. The equation now appears as \[4x-3x=19-5\]
Now x is taken as common in the left hand side, the equation now appears as
\[x\left( 4-3 \right)=19-5\]
Adding all the terms in the right hand side, The equation now appears as \[x=14\] .
Therefore, the value of x is 14.
Note: This is a direct problem where the value of x can be found by moving the terms from L.H.S to R.H.S and performing mathematical expressions. To check placing the value of x in the above equation gives L.H.S = R.H.S. In questions as above the only possible mistake that a student can make is either in the calculation part or a sign error, so be careful about the two points where the error can be made.
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