Question

Solve the given equation: 44=8+(t+2).

Answer 1

Hint: In this question, we have been given an equation, So, to start the solving of the equation, we subtract 8 from both the sides of the equation to get an equation whose RHS is t+2. Now to get the value of t, again subtract 2 from both the sides of the resulting equation and solve.

Complete step-by-step answer:
The given equation is
 \[44=8+\left( t+2 \right)\]
We know that an equation remains valid if we add or subtract the same number both in the Left Hand Side (LHS) and Right Hand Side (RHS). Therefore, we should subtract a number on both sides such that only t+2 remains on the RHS. As 8 is present as a separate term in RHS, we can subtract 8 from both sides in equation to obtain
$\begin{align}
  & 44-8=8+\left( t+2 \right)-8 \\
 & \Rightarrow 36=t+2 \\
 & \Rightarrow t+2=36 \\
\end{align}$
Again, to get the value of t, we will subtract 2 from both sides of the final resulting equation. On doing so, we get
$\begin{align}
  & t+2-2=36-2 \\
 & \Rightarrow t=34 \\
\end{align}$
Therefore, the possible value of t that satisfies the equation \[44=8+\left( t+2 \right)\] is t=34.

Note: You should remember that multiplying, adding, subtracting, or dividing the LHS and RHS of an equation by the same number gives other equation which is true, however you should not divide both sides of an equation by 0, as that would give non determinate values on the both sides of the equation. You could have also solved the above equation by directly writing \[44=8+\left( t+2 \right)\] as 44=8+t+2 and subtracting 10 from both the sides of the equation.