Question

Solve the fraction using Vedic mathematics: \[\dfrac{6}{11}-\dfrac{3}{5}\].

Answer 1

Hint: In this question, we have to take \[11\times 5\] as LCM and then solve further. In the numerator, we have
\[30-33\] and 55 as the denominator. Now, simplify this and solve it further.

Complete step-by-step solution -
According to the question, we have two fraction terms and we have to subtract \[\dfrac{3}{5}\] from \[\dfrac{6}{11}\].
Our main target is to find LCM of 5 and 11. The LCM of 5 and 11 is 55.
Now solving,
\[\begin{align}
  & \dfrac{6}{11}-\dfrac{3}{5} \\
 & =\dfrac{30-33}{55} \\
\end{align}\]
Now, subtracting 33 from 30 in the numerator side, we get
\[\begin{align}
  & =\dfrac{30-33}{55} \\
 & =\dfrac{-3}{55} \\
\end{align}\]
Hence, the value of \[\dfrac{6}{11}-\dfrac{3}{5}\] is \[\dfrac{-3}{55}\] .

Note: In this question, one can make mistakes in the multiplication of terms in numerators. In this situation, one can multiply 6 by 11 which is wrong. If we have to find the terms which are to be multiplied in the numerator of the fraction, then divide the LCM by denominator. In this question, LCM is 55, and the denominator of the fraction \[\dfrac{6}{11}\] is 11. After dividing the LCM by denominator, we get \[\dfrac{55}{11}=5\] . So, 5 should be multiplied in the numerator of the fraction \[\dfrac{6}{11}\]. Here, the numerator of the fraction is 6.