
How do you solve the following system $ - 3y + x = - 3, - 5x - y = 14 $ ?
Answer
549.6k+ views
Hint: In order to determine the solution of a given system of equation having two variables, use the method of elimination of term by eliminating the $ x $ term by multiplying by making the mod of coefficient of x in both the equation equal. Then apply the operation of addition or subtraction according to the equations obtained to eliminate x term. Solve the result for $ y $ and put the obtained value of $ y $ in any of the equations given to get the value of $ x $ .
Complete step-by-step answer:
We are given pair of linear equation in two variables $ - 3y + x = - 3, - 5x - y = 14 $
$ - 3y + x = - 3 $ ---(1)
$ - 5x - y = 14 $ ----(2)
In order to solve the system of equations, we have many methods like, substitution, elimination of term, and cross-multiplication.
Here we will be using an elimination method to eliminate the term having $ x $ from both the equations.
And to do so we have to first make the mod of coefficient of $ x $ in both the equation equal to each.
In the second equation the coefficient of x is 5, so multiplying both side of the equation (1) with the number 5, we get
$
\Rightarrow 5\left( { - 3y + x} \right) = 5\left( { - 3} \right) \\
- 15y + 5x = - 15 \;
$
Now adding the above equation with the equation(2) , we get
\[
- 15y + 5x - 5x - y = - 15 + 14 \\
- 16y = - 1 \;
\]
Solving the equation for variable $ y $
$ y = \dfrac{1}{{16}} $
Hence we have obtained the value of $ y = \dfrac{1}{{16}} $ .
Now putting this value of y in the equation(1) to get the value of x
$
\dfrac{{ - 3}}{{16}} + x = - 3 \\
x = - 3 + \dfrac{3}{{16}} \\
x = \dfrac{{ - 48 + 3}}{{16}} \\
x = \dfrac{{ - 45}}{{16}} \;
$
Therefore the solution of system of equation given is $ x = - \dfrac{{45}}{{16}} \; and \;y = \dfrac{1}{{16}} $
So, the correct answer is “$ x = - \dfrac{{45}}{{16}} \; and \;y = \dfrac{1}{{16}} $ ”.
Note: Linear Equation in two variable: A linear equation is a equation which can be represented in the form of $ ax + by + c $ where $ x $ and $ y $ are the unknown variables and c is the number known where $ a \ne 0,b \ne 0 $ .
The degree of the variable in the linear equation is of the order 1.
1. One must be careful while calculating the answer as calculation error may come.
2. Solution of two linear equations can be done by using elimination method , substitution method and cross multiplication method .
3.Its not compulsory to always eliminate the term with $ x $ . We have to judge according to the equation whose term elimination cost is less.
Complete step-by-step answer:
We are given pair of linear equation in two variables $ - 3y + x = - 3, - 5x - y = 14 $
$ - 3y + x = - 3 $ ---(1)
$ - 5x - y = 14 $ ----(2)
In order to solve the system of equations, we have many methods like, substitution, elimination of term, and cross-multiplication.
Here we will be using an elimination method to eliminate the term having $ x $ from both the equations.
And to do so we have to first make the mod of coefficient of $ x $ in both the equation equal to each.
In the second equation the coefficient of x is 5, so multiplying both side of the equation (1) with the number 5, we get
$
\Rightarrow 5\left( { - 3y + x} \right) = 5\left( { - 3} \right) \\
- 15y + 5x = - 15 \;
$
Now adding the above equation with the equation(2) , we get
\[
- 15y + 5x - 5x - y = - 15 + 14 \\
- 16y = - 1 \;
\]
Solving the equation for variable $ y $
$ y = \dfrac{1}{{16}} $
Hence we have obtained the value of $ y = \dfrac{1}{{16}} $ .
Now putting this value of y in the equation(1) to get the value of x
$
\dfrac{{ - 3}}{{16}} + x = - 3 \\
x = - 3 + \dfrac{3}{{16}} \\
x = \dfrac{{ - 48 + 3}}{{16}} \\
x = \dfrac{{ - 45}}{{16}} \;
$
Therefore the solution of system of equation given is $ x = - \dfrac{{45}}{{16}} \; and \;y = \dfrac{1}{{16}} $
So, the correct answer is “$ x = - \dfrac{{45}}{{16}} \; and \;y = \dfrac{1}{{16}} $ ”.
Note: Linear Equation in two variable: A linear equation is a equation which can be represented in the form of $ ax + by + c $ where $ x $ and $ y $ are the unknown variables and c is the number known where $ a \ne 0,b \ne 0 $ .
The degree of the variable in the linear equation is of the order 1.
1. One must be careful while calculating the answer as calculation error may come.
2. Solution of two linear equations can be done by using elimination method , substitution method and cross multiplication method .
3.Its not compulsory to always eliminate the term with $ x $ . We have to judge according to the equation whose term elimination cost is less.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

What are the 12 elements of nature class 8 chemistry CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Full form of STD, ISD and PCO

Convert 40circ C to Fahrenheit A 104circ F B 107circ class 8 maths CBSE

Advantages and disadvantages of science


