How do you solve the following system $ - 2x + 5y = 20,x + 4y = 16 $ ?
Answer
570.9k+ views
Hint: In order to determine the solution of a given system of equations having two variables, use the method of elimination of term by eliminating the $ x $ term by making the mod of coefficient of $ x $ in both the equations equal. Then apply the operation of addition or subtraction between the equation to eliminate $ x $ term. Solve the result for $ y $ and put the obtained value of $ y $ in any of the equations given to get the value of $ x $ .
Complete step by step solution:
We are given pair of linear equation in two variables $ - 2x + 5y = 20,x + 4y = 16 $
$ - 2x + 5y = 20 $ ---(1)
$ x + 4y = 16 $ ----(2)
In order to solve the system of equations, we have many methods like, substitution, elimination of term, and cross-multiplication.
Here we will be using an elimination method to eliminate the term having $ x $ from both the equations.
And to do so we have to first make the mod of coefficient of $ x $ in both the equation equal to each.
In the first equation the mod of coefficient of $ x $ is 2, so multiplying both side of the equation (2) with the number 2, we get
$
\Rightarrow 2\left( {x + 4y} \right) = 2\left( {16} \right) \\
2x + 8y = 32 \;
$
Now Adding the above equation with the equation (1) , we get
$ - 2x + 5y + 2x + 8y = 32 + 20 $
Combining like terms we get
\[13y = 52\]
Solving the equation for variable $ y $ by dividing both sides of the equation with the coefficient of $ y $ i.e. $ 13 $
\[
\Rightarrow \dfrac{{13y}}{{13}} = \dfrac{{52}}{{13}} \\
y = 4 \;
\]
Hence, we have obtained the value of \[y = 4\].
Now putting this value of $ y $ in the equation (1) to get the value of $ x $
$
\Rightarrow - 2x + 5\left( 4 \right) = 20 \\
- 2x + 20 = 20 \\
- 2x = 0 \\
x = 0 \;
$
Therefore, the solution of system of given equations is $ x = 0,y = 4 $
So, the correct answer is “ $ x = 0,y = 4 $ ”.
Note: Linear Equation in two variable: A linear equation is a equation which can be represented in the form of $ ax + by + c $ where $ x $ and $ y $ are the unknown variables and c is the number known where $ a \ne 0,b \ne 0 $ .
The degree of the variable in the linear equation is of the order 1.
1. One must be careful while calculating the answer as calculation error may come.
2. Solution of two linear equations can be done by using elimination method, substitution method and cross multiplication method.
Complete step by step solution:
We are given pair of linear equation in two variables $ - 2x + 5y = 20,x + 4y = 16 $
$ - 2x + 5y = 20 $ ---(1)
$ x + 4y = 16 $ ----(2)
In order to solve the system of equations, we have many methods like, substitution, elimination of term, and cross-multiplication.
Here we will be using an elimination method to eliminate the term having $ x $ from both the equations.
And to do so we have to first make the mod of coefficient of $ x $ in both the equation equal to each.
In the first equation the mod of coefficient of $ x $ is 2, so multiplying both side of the equation (2) with the number 2, we get
$
\Rightarrow 2\left( {x + 4y} \right) = 2\left( {16} \right) \\
2x + 8y = 32 \;
$
Now Adding the above equation with the equation (1) , we get
$ - 2x + 5y + 2x + 8y = 32 + 20 $
Combining like terms we get
\[13y = 52\]
Solving the equation for variable $ y $ by dividing both sides of the equation with the coefficient of $ y $ i.e. $ 13 $
\[
\Rightarrow \dfrac{{13y}}{{13}} = \dfrac{{52}}{{13}} \\
y = 4 \;
\]
Hence, we have obtained the value of \[y = 4\].
Now putting this value of $ y $ in the equation (1) to get the value of $ x $
$
\Rightarrow - 2x + 5\left( 4 \right) = 20 \\
- 2x + 20 = 20 \\
- 2x = 0 \\
x = 0 \;
$
Therefore, the solution of system of given equations is $ x = 0,y = 4 $
So, the correct answer is “ $ x = 0,y = 4 $ ”.
Note: Linear Equation in two variable: A linear equation is a equation which can be represented in the form of $ ax + by + c $ where $ x $ and $ y $ are the unknown variables and c is the number known where $ a \ne 0,b \ne 0 $ .
The degree of the variable in the linear equation is of the order 1.
1. One must be careful while calculating the answer as calculation error may come.
2. Solution of two linear equations can be done by using elimination method, substitution method and cross multiplication method.
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