
Solve the following statement sum.
The sum of the two consecutive multiples of 5 is 55. Find these multiples.
Answer
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Hint: Here, multiples of 5 are to be listed first and then we have to sum two consecutive numbers i.e. one number next to the other number and have to check whether their sum is 55 or not. If yes, then those are the multiples of the given question.
Complete step-by-step answer:
Here, let’s find all the multiples o5 5. So, it is basically a table of 5 which is given as 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, …….so on.
So now, taking the first 2 numbers i.e. 5 and 10. On adding these two we get a total $5+10=15$ . So, the sum is not 55 so, this is not the multiples which we are finding.
Taking the next 2 i.e. 10 and 15, we get a total $10+15=25$ . So, these are not multiples as summation is not 55.
Taking the next 2 i.e. 15 and 20, we get a total $15+20=35$ . So, these are not multiples as summation is not 55.
Taking the next 2 i.e. 20 and 25, we get a total $20+25=45$ . So, these are not multiples as summation is not 55.
Taking the next 2 i.e. 25 and 30, we get a total $25+30=55$ . So, these are multiples as summation is 55.
Now, there is no need to calculate further.
Thus, two consecutive multiples of 5 in addition gives sum 55 is 25, 30.
Note: Another approach to this problem is by using the formula $5n$ or $5\left( n+1 \right)$ for finding multiples of 5. So, substituting the value of n from 0 to n, we get the series as $5\left( 1 \right),5\left( 2 \right),5\left( 3 \right),5\left( 4 \right),....$. On solving this, we can get the series as 5, 10, 15, 20, 25, 30, 35, …….so on. From this also we can find by adding two consecutive numbers and check whose addition is equal to 55. Hence, we get the same answer.
Complete step-by-step answer:
Here, let’s find all the multiples o5 5. So, it is basically a table of 5 which is given as 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, …….so on.
So now, taking the first 2 numbers i.e. 5 and 10. On adding these two we get a total $5+10=15$ . So, the sum is not 55 so, this is not the multiples which we are finding.
Taking the next 2 i.e. 10 and 15, we get a total $10+15=25$ . So, these are not multiples as summation is not 55.
Taking the next 2 i.e. 15 and 20, we get a total $15+20=35$ . So, these are not multiples as summation is not 55.
Taking the next 2 i.e. 20 and 25, we get a total $20+25=45$ . So, these are not multiples as summation is not 55.
Taking the next 2 i.e. 25 and 30, we get a total $25+30=55$ . So, these are multiples as summation is 55.
Now, there is no need to calculate further.
Thus, two consecutive multiples of 5 in addition gives sum 55 is 25, 30.
Note: Another approach to this problem is by using the formula $5n$ or $5\left( n+1 \right)$ for finding multiples of 5. So, substituting the value of n from 0 to n, we get the series as $5\left( 1 \right),5\left( 2 \right),5\left( 3 \right),5\left( 4 \right),....$. On solving this, we can get the series as 5, 10, 15, 20, 25, 30, 35, …….so on. From this also we can find by adding two consecutive numbers and check whose addition is equal to 55. Hence, we get the same answer.
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