Question

Solve the following simple equation: $8x + \dfrac{5}{2} = 13$

Answer 1

Hint: We are going to make use of the basic operations, The addition is the sum of given two or more than two numbers, or variables and in addition, if we sum the two or more numbers then we obtain a new frame of the number will be found, which can be represented as $ + $ , also in subtraction which is the minus of given two or more than two numbers, but here comes with the condition that in subtraction the greater number sign represented in the number will stay constant example $2 - 3 = - 1$

Complete step by step answer:
Given that the equation is $8x + \dfrac{5}{2} = 13$ and then we need to find the value of the unknown variable $x$, so we will make use of the basic mathematical operations to simplify further.
Using the subtraction operation, subtract the number $\dfrac{5}{2}$ on both sides, then we get \[8x + \dfrac{5}{2} - \dfrac{5}{2} = 13 - \dfrac{5}{2}\]
Since equal values with opposite signs get cancel, then we have \[8x = 13 - \dfrac{5}{2}\]
Now using the cross-multiplication method, we have \[8x = 13 - \dfrac{5}{2} \Rightarrow 8x = \dfrac{{26 - 5}}{2}\]
Again, by subtraction we get \[8x = \dfrac{{21}}{2}\]
Finally, by the division and multiplication, we have \[x = \dfrac{{21}}{2} \times \dfrac{1}{8} = \dfrac{{21}}{{16}}\] and hence which is the unknown value of the given variable $x = \dfrac{{21}}{{16}}$

Note:
The other two operations are multiplication and division operations.
Since multiplicand refers to the number multiplied. Also, a multiplier refers to multiplying the first number. Have a look at an example; while multiplying $5 \times 7$the number $5$ is called the multiplicand and the number $7$ is called the multiplier. Like $2 \times 3 = 6$ or which can be also expressed in the form of $2 + 2 + 2(3times)$
The process of the inverse of the multiplication method is called division. Like $x \times y = z$ is multiplication thus the division sees as $x = \dfrac{z}{y}$. Like $x = \dfrac{{21}}{2} \times \dfrac{1}{8} = \dfrac{{21}}{{16}} \Rightarrow x = 1.3125$