Solve the following given expression: \[\dfrac{{\dfrac{1}{2} \div 4 + 20}}{{\dfrac{1}{2} \times 4 + 20}}\]
Answer
641.4k+ views
Hint: The division by 4 can be written as the multiplication by reciprocal of 4 and by using the BODMAS rule, we can simplify the expression to get the final answer.
Complete step-by-step answer:
BODMAS rule gives the priority of the arithmetic operations. BODMAS stands for Bracket, Of, Division, Multiplication, Addition, and Subtraction. This is the order of preference too, with brackets being first evaluated and subtraction being evaluated last.
Hence, in the expression \[\dfrac{{\dfrac{1}{2} \div 4 + 20}}{{\dfrac{1}{2} \times 4 + 20}}\], we need to solve the division first.
The division by any number can also be written as a multiplication by its reciprocal. The division by number 4 can be written as a multiplication by the reciprocal of 4, that is, \[\dfrac{1}{4}\]. Hence, we have:
\[\dfrac{{\dfrac{1}{2} \div 4 + 20}}{{\dfrac{1}{2} \times 4 + 20}} = \dfrac{{\dfrac{1}{2} \times \dfrac{1}{4} + 20}}{{\dfrac{1}{2} \times 4 + 20}}\]
Next, we multiply the numbers in the numerator and denominator.
\[\dfrac{{\dfrac{1}{2} \div 4 + 20}}{{\dfrac{1}{2} \times 4 + 20}} = \dfrac{{\dfrac{1}{8} + 20}}{{2 + 20}}\]
As the next step, we add the numbers in the numerator and the denominator. The terms in the numerator can be added by multiplying 20 with 8 and adding to 1 and dividing by 8 again.
\[\dfrac{{\dfrac{1}{2} \div 4 + 20}}{{\dfrac{1}{2} \times 4 + 20}} = \dfrac{{\dfrac{{1 + 20 \times 8}}{8}}}{{22}}\]
Again, solving the multiplication first, we have:
\[\dfrac{{\dfrac{1}{2} \div 4 + 20}}{{\dfrac{1}{2} \times 4 + 20}} = \dfrac{{\dfrac{{1 + 160}}{8}}}{{22}}\]
We now add 1 and 160 to get 161.
\[\dfrac{{\dfrac{1}{2} \div 4 + 20}}{{\dfrac{1}{2} \times 4 + 20}} = \dfrac{{\dfrac{{161}}{8}}}{{22}}\]
We now have fraction inside a fraction, this can be easily solved to write in the simplest form. It is just 161 divided by 8 divided by 22, hence, we just multiply 8 and 22 and divide it with 161.
\[\dfrac{{\dfrac{1}{2} \div 4 + 20}}{{\dfrac{1}{2} \times 4 + 20}} = \dfrac{{161}}{{8 \times 22}}\]
The answer when 8 is multiplied with 22 is 176. Hence, we have:
\[\dfrac{{\dfrac{1}{2} \div 4 + 20}}{{\dfrac{1}{2} \times 4 + 20}} = \dfrac{{161}}{{176}}\]
Hence, the simplest form of the given expression is \[\dfrac{{161}}{{176}}\].
Note: You may commit a mistake when dividing \[\dfrac{1}{2}\] by 4 and write the answer as 2 but the correct answer is \[\dfrac{1}{8}\]. Also first multiply, then do the addition.Whenever we try to solve these types of problems, apply the BODMAS rule for arithmetic operations to get the correct answer.
Complete step-by-step answer:
BODMAS rule gives the priority of the arithmetic operations. BODMAS stands for Bracket, Of, Division, Multiplication, Addition, and Subtraction. This is the order of preference too, with brackets being first evaluated and subtraction being evaluated last.
Hence, in the expression \[\dfrac{{\dfrac{1}{2} \div 4 + 20}}{{\dfrac{1}{2} \times 4 + 20}}\], we need to solve the division first.
The division by any number can also be written as a multiplication by its reciprocal. The division by number 4 can be written as a multiplication by the reciprocal of 4, that is, \[\dfrac{1}{4}\]. Hence, we have:
\[\dfrac{{\dfrac{1}{2} \div 4 + 20}}{{\dfrac{1}{2} \times 4 + 20}} = \dfrac{{\dfrac{1}{2} \times \dfrac{1}{4} + 20}}{{\dfrac{1}{2} \times 4 + 20}}\]
Next, we multiply the numbers in the numerator and denominator.
\[\dfrac{{\dfrac{1}{2} \div 4 + 20}}{{\dfrac{1}{2} \times 4 + 20}} = \dfrac{{\dfrac{1}{8} + 20}}{{2 + 20}}\]
As the next step, we add the numbers in the numerator and the denominator. The terms in the numerator can be added by multiplying 20 with 8 and adding to 1 and dividing by 8 again.
\[\dfrac{{\dfrac{1}{2} \div 4 + 20}}{{\dfrac{1}{2} \times 4 + 20}} = \dfrac{{\dfrac{{1 + 20 \times 8}}{8}}}{{22}}\]
Again, solving the multiplication first, we have:
\[\dfrac{{\dfrac{1}{2} \div 4 + 20}}{{\dfrac{1}{2} \times 4 + 20}} = \dfrac{{\dfrac{{1 + 160}}{8}}}{{22}}\]
We now add 1 and 160 to get 161.
\[\dfrac{{\dfrac{1}{2} \div 4 + 20}}{{\dfrac{1}{2} \times 4 + 20}} = \dfrac{{\dfrac{{161}}{8}}}{{22}}\]
We now have fraction inside a fraction, this can be easily solved to write in the simplest form. It is just 161 divided by 8 divided by 22, hence, we just multiply 8 and 22 and divide it with 161.
\[\dfrac{{\dfrac{1}{2} \div 4 + 20}}{{\dfrac{1}{2} \times 4 + 20}} = \dfrac{{161}}{{8 \times 22}}\]
The answer when 8 is multiplied with 22 is 176. Hence, we have:
\[\dfrac{{\dfrac{1}{2} \div 4 + 20}}{{\dfrac{1}{2} \times 4 + 20}} = \dfrac{{161}}{{176}}\]
Hence, the simplest form of the given expression is \[\dfrac{{161}}{{176}}\].
Note: You may commit a mistake when dividing \[\dfrac{1}{2}\] by 4 and write the answer as 2 but the correct answer is \[\dfrac{1}{8}\]. Also first multiply, then do the addition.Whenever we try to solve these types of problems, apply the BODMAS rule for arithmetic operations to get the correct answer.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

Class 5 Social Science Question Answers

Describe one incident when you got into trouble because class 5 english CBSE

Which are the Top 10 Largest Countries of the World?

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is the Full Form of ICSE / ISC ?

