Solve the following equation for ‘x’.
$5(x-3)=3(x+2)$
Answer
635.4k+ views
Hint: Remove the brackets by multiplying the terms of L.H.S by 5 and the terms of R.H.S by 3, as provided in the question. Now, take the terms containing ‘x’ to the left hand side and the constant terms to the right hand side. Apply simple addition and subtraction to simplify the terms. Find the value of x to get the answer.
Complete step-by-step answer:
We have been provided with the equation: $5(x-3)=3(x+2)$. We have to solve this equation, that means, we have to find the value of x.
As we can see that, this is a linear equation in one variable, which is x. Therefore,
Removing the brackets by multiplying the terms of L.H.S by 5 and the terms of R.H.S by 3, we get,
$5x-15=3x+6$
Taking the terms containing ‘x’ to the L.H.S and the constant terms to the R.H.S, we get,
$\begin{align}
& 5x-3x=6+15 \\
& 2x=21 \\
& x=\dfrac{21}{2} \\
\end{align}$
Hence, the value of x is $\dfrac{21}{2}$.
Note: One may note that we have been provided with a single equation only. The reason is that, we have to find the value of only one variable, that is x. So, if we have to solve an equation having ‘n’ number of variables then we should be provided with ‘n’ equations. Now, one can check the answer by substituting the obtained value of ‘x’ in the equation provided in the question. We have to determine the value of L.H.S and R.H.S separately and if they are equal then our answer is correct.
Complete step-by-step answer:
We have been provided with the equation: $5(x-3)=3(x+2)$. We have to solve this equation, that means, we have to find the value of x.
As we can see that, this is a linear equation in one variable, which is x. Therefore,
Removing the brackets by multiplying the terms of L.H.S by 5 and the terms of R.H.S by 3, we get,
$5x-15=3x+6$
Taking the terms containing ‘x’ to the L.H.S and the constant terms to the R.H.S, we get,
$\begin{align}
& 5x-3x=6+15 \\
& 2x=21 \\
& x=\dfrac{21}{2} \\
\end{align}$
Hence, the value of x is $\dfrac{21}{2}$.
Note: One may note that we have been provided with a single equation only. The reason is that, we have to find the value of only one variable, that is x. So, if we have to solve an equation having ‘n’ number of variables then we should be provided with ‘n’ equations. Now, one can check the answer by substituting the obtained value of ‘x’ in the equation provided in the question. We have to determine the value of L.H.S and R.H.S separately and if they are equal then our answer is correct.
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