Solve the following equation for \[0<\theta <\dfrac{\pi }{2}\] :
\[\tan \theta +\tan 2\theta +\tan 3\theta =0\]
A. \[\tan \theta =0\]
B. \[\tan 2\theta =0\]
C. \[\tan 3\theta =0\]
D. \[\tan \theta \tan 2\theta =2\]
Answer
628.5k+ views
Hint: Split the \[\tan 3\theta \] by using the formula \[\tan \left( A+B \right)=\dfrac{\tan A+\tan B}{1-\tan A\tan B}\] where A= \[2\theta \] and B= \[\theta \] here A and B values are taken like that because the problem is in terms of \[\theta \] , \[2\theta \] . After substituting the obtained expression in the given expression then we will get two values.
Complete step-by-step answer:
Given that \[0 < \theta < \dfrac{\pi }{2}\]
\[\tan \theta +\tan 2\theta +\tan 3\theta =0\] . . . . . . . . . . . . . . . . . . . . . . . . . . . (1)
We can write the \[\tan 3\theta \] as follows
\[\tan 3\theta =\tan \left( 2\theta +\theta \right)\]
\[\Rightarrow \tan 3\theta =\dfrac{\tan 2\theta +\tan \theta }{1-\tan 2\theta \tan \theta }\]
Cross multiplying the above equation we will get as follows,
\[\Rightarrow \tan 3\theta -\tan 2\theta \tan \theta \tan 3\theta =\tan 2\theta +\tan \theta \] . . . . . . . . . . . . . . . . . . . . . (2)
Now substitute the value of equation (2) in the equation (1) then we will get,
\[\Rightarrow \tan \theta +\tan 2\theta +\tan 3\theta =0\]
\[\Rightarrow \tan 3\theta -\tan 2\theta \tan \theta \tan 3\theta +\tan 3\theta =0\]
\[\Rightarrow 2\tan 3\theta -\tan 2\theta \tan \theta \tan 3\theta =0\]
Now take \[\tan 3\theta \] common from each term then we will get,
\[\Rightarrow \tan 3\theta \left[ 2-\tan 2\theta \tan \theta \right] =0\] . . . . . . . . . . . . . . . . . (3)
Case-1
\[\tan 3\theta =0\] . . . . . . . . . . . . (4)
Case-2
\[2-\tan 2\theta \tan \theta =0\]
\[\Rightarrow \tan \theta \tan 2\theta =2\] . . . . . . . . . . . . . . (5)
So the correct option for above question is option (C) and option (D).
Note: To solve this type of problems we have to know trigonometric formulas like formula for expansion of \[\tan \left( A+B \right)\] . In trigonometric problems first we have to remember all formulas related to the problem and use the formula in which we will get the required answer. Generally by seeing the problem we will understand the approach to the problem.
Complete step-by-step answer:
Given that \[0 < \theta < \dfrac{\pi }{2}\]
\[\tan \theta +\tan 2\theta +\tan 3\theta =0\] . . . . . . . . . . . . . . . . . . . . . . . . . . . (1)
We can write the \[\tan 3\theta \] as follows
\[\tan 3\theta =\tan \left( 2\theta +\theta \right)\]
\[\Rightarrow \tan 3\theta =\dfrac{\tan 2\theta +\tan \theta }{1-\tan 2\theta \tan \theta }\]
Cross multiplying the above equation we will get as follows,
\[\Rightarrow \tan 3\theta -\tan 2\theta \tan \theta \tan 3\theta =\tan 2\theta +\tan \theta \] . . . . . . . . . . . . . . . . . . . . . (2)
Now substitute the value of equation (2) in the equation (1) then we will get,
\[\Rightarrow \tan \theta +\tan 2\theta +\tan 3\theta =0\]
\[\Rightarrow \tan 3\theta -\tan 2\theta \tan \theta \tan 3\theta +\tan 3\theta =0\]
\[\Rightarrow 2\tan 3\theta -\tan 2\theta \tan \theta \tan 3\theta =0\]
Now take \[\tan 3\theta \] common from each term then we will get,
\[\Rightarrow \tan 3\theta \left[ 2-\tan 2\theta \tan \theta \right] =0\] . . . . . . . . . . . . . . . . . (3)
Case-1
\[\tan 3\theta =0\] . . . . . . . . . . . . (4)
Case-2
\[2-\tan 2\theta \tan \theta =0\]
\[\Rightarrow \tan \theta \tan 2\theta =2\] . . . . . . . . . . . . . . (5)
So the correct option for above question is option (C) and option (D).
Note: To solve this type of problems we have to know trigonometric formulas like formula for expansion of \[\tan \left( A+B \right)\] . In trigonometric problems first we have to remember all formulas related to the problem and use the formula in which we will get the required answer. Generally by seeing the problem we will understand the approach to the problem.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

In what year Guru Nanak Dev ji was born A15 April 1469 class 11 social science CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

