Question

Solve the following equation: - $-4=5\left( p-2 \right)$.

Answer 1

Hint: First of all remove the bracket by multiplying 5 with each of the term inside the bracket in the R.H.S. Take the terms containing the variable p to the L.H.S and all the constant terms to the R.H.S. Now, simplify both the sides with the help of simple arithmetic operations like addition and subtraction. Finally, divide both the sides with the coefficient of p and simplify the R.H.S to get the answer.

Complete step-by-step answer:
Here we have been provided with the linear equation $-4=5\left( p-2 \right)$ and we are asked to solve it. That means we have to find the value of p.
$\because -4=5\left( p-2 \right)$
Removing the bracket in the R.H.S by multiplying 5 with each term inside the bracket we get,
$\Rightarrow -4=5p-10$
Now, taking all the terms containing the variable p to the L.H.S. and taking all the constant terms to the R.H.S we get,
\[\begin{align}
  & \Rightarrow -5p=4-10 \\
 & \Rightarrow -5p=-6 \\
\end{align}\]
Dividing both the sides with the coefficient of p, i.e. (-6), and simplifying using the relation $\left( -1 \right)\div \left( -1 \right)=1$ we get,
\[\therefore p=\dfrac{6}{5}\]
Hence, the value of p is $\dfrac{6}{5}$.

Note: If you want to check the answer then just substitute the obtained value of p in the equation provided in the question. Solve for the L.H.S and R.H.S expression separately and if they are equal then our answer is correct otherwise there may be some calculation mistake which must be corrected. You can also solve the question by dividing both the sides with 5 at the initial step and then taking the constant terms at one side.