Solve the following equation: $ 2x + 6 = 7x - 8 $ .
Answer
585k+ views
Hint: The given equation is a one-step equation. If we perform any operation of addition, subtraction, multiplication and division with the same number on both sides of the equation, then the both sides of the equation will remain equal.
Complete step by step solution:
In this problem, we have given an equation $ 2x + 6 = 7x - 8 $ . Now, to solve the equation we need to add $ 8 $ on both sides of the equation and on adding we get,
$ \Rightarrow 2x + 6 + 8 = 7x - 8 + 8 $
On further solving, we get,
$ \Rightarrow 2x + 14 = 7x $
Now, we will subtract $ 14 $ from both the sides of the equation,
$ \Rightarrow 2x + 14 - 14 = 7x - 14 $
On further solving, we get,
$ \Rightarrow 2x = 7x - 14 $
Now, we will subtract $ 2x $ from both the sides,
$ \Rightarrow 2x - 2x = 7x - 14 - 2x $
Only the like terms, whose variables are the same can be added or subtracted. Now, on further solving, we get,
$ \Rightarrow 0 = 5x - 14 $
Now, we will add $ 14 $ on both sides of the equation,
$ \Rightarrow 0 + 14 = 5x - 14 + 14 $
On further solving, we get,
$ \Rightarrow 14 = 5x $
Now, we will divide the whole equation by $ 5 $ ,
$ \Rightarrow \dfrac{{14}}{5} = \dfrac{5}{5}x $
On further solving, we get,
$ \Rightarrow \dfrac{{14}}{5} = x $
Hence, the value of x is $ \dfrac{{14}}{5} $ .
So, the correct answer is “ $ \dfrac{{14}}{5} $ ”.
Note: We can also solve the given equation in the question by taking like terms on one side and then solving it, when the positive term goes from one side of the equation to the other then it becomes negative and vice versa and when the number is in the multiplication with the other and when it goes from one side to other then this will divide the other number and vice versa.
Complete step by step solution:
In this problem, we have given an equation $ 2x + 6 = 7x - 8 $ . Now, to solve the equation we need to add $ 8 $ on both sides of the equation and on adding we get,
$ \Rightarrow 2x + 6 + 8 = 7x - 8 + 8 $
On further solving, we get,
$ \Rightarrow 2x + 14 = 7x $
Now, we will subtract $ 14 $ from both the sides of the equation,
$ \Rightarrow 2x + 14 - 14 = 7x - 14 $
On further solving, we get,
$ \Rightarrow 2x = 7x - 14 $
Now, we will subtract $ 2x $ from both the sides,
$ \Rightarrow 2x - 2x = 7x - 14 - 2x $
Only the like terms, whose variables are the same can be added or subtracted. Now, on further solving, we get,
$ \Rightarrow 0 = 5x - 14 $
Now, we will add $ 14 $ on both sides of the equation,
$ \Rightarrow 0 + 14 = 5x - 14 + 14 $
On further solving, we get,
$ \Rightarrow 14 = 5x $
Now, we will divide the whole equation by $ 5 $ ,
$ \Rightarrow \dfrac{{14}}{5} = \dfrac{5}{5}x $
On further solving, we get,
$ \Rightarrow \dfrac{{14}}{5} = x $
Hence, the value of x is $ \dfrac{{14}}{5} $ .
So, the correct answer is “ $ \dfrac{{14}}{5} $ ”.
Note: We can also solve the given equation in the question by taking like terms on one side and then solving it, when the positive term goes from one side of the equation to the other then it becomes negative and vice versa and when the number is in the multiplication with the other and when it goes from one side to other then this will divide the other number and vice versa.
Recently Updated Pages
Match columnI with columnII and choose the correct class 12 biology NEET_UG

Match columnI with columnII and choose the correct class 12 biology NEET_UG

Match columnI with columnII and choose the correct class 12 biology NEET_UG

Which plant will lose its economic value if its fruits class 12 biology NEET_UG

The given figure shows two endocrine glands marked class 11 biology NEET_UG

Human insulin is being commercially produced from a class 12 biology NEET_UG

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

One cusec is equal to how many liters class 8 maths CBSE

Give me the opposite gender of Duck class 8 english CBSE

Answer the following in a phrase or sentence Why did class 8 english CBSE

Full form of STD, ISD and PCO


