Question

Solve the following: $\dfrac{8x-3}{3x}=2$.

Answer 1

Hint:Multiply both the L.H.S and R.H.S by ‘3x’ to make the expression free from fraction. Now, take the terms containing ‘x’ to the left hand side and the constant terms to the right hand side. Find the value of x to get the answer.

Complete step-by-step answer:

We have been provided with the equation: $\dfrac{8x-3}{3x}=2$. We have to solve this equation, that means, we have to find the value of x.
As we can see that, this is a linear equation in one variable, which is x. Therefore,
Multiplying both sides by 3x, we get,
$\begin{align}
  & 3x\times \dfrac{8x-3}{3x}=2\times 3x \\
 & \Rightarrow 8x-3=6x \\
\end{align}$
Taking the terms containing ‘x’ to the L.H.S and the constant terms to the R.H.S, we get,
$\begin{align}
  & 8x-6x=3 \\
 & 2x=3 \\
 & x=\dfrac{3}{2} \\
\end{align}$
Hence, the value of x is $\dfrac{3}{2}$.

Note: One may note that we have been provided with a single equation only. The reason is that, we have to find the value of only one variable, that is x. So, if we have to solve an equation having ‘n’ number of variables then we should be provided with ‘n’ equations. Now, one can apply other methods also to solve this question. You can take the R.H.S term to the left hand side and take the L.C.M. Now, to remove fraction, multiply both sides with ‘3x’. The final equation will be the same.