Solve the following:
\[500\times 3+6\div 6-4\].
Answer
615.6k+ views
Hint: According to BODMAS rule, it is clear that the brackets are placed in the order of division, multiplication, addition and subtraction. By using this BODMAS rule, we can find the value of \[500\times 3+6\div 6-4\].
Complete step by step answer:
Before solving this problem, we should know about the BODMAS rule. According to BODMAS rule, it is clear that the brackets are placed in the order of division, multiplication, addition and subtraction.
So, let us assume the value of \[500\times 3+6\div 6-4\] is equal to A.
\[\Rightarrow A=500\times 3+6\div 6-4....(1)\]
According to BODMAS rule, in A first division takes place.
\[\begin{align}
& \Rightarrow A=500\times 3+\left( 6\div 6 \right)-4 \\
& \Rightarrow A=500\times 3+1-4 \\
\end{align}\]
According to BODMAS rule, now in A multiplication takes place.
\[\begin{align}
& \Rightarrow A=\left( 500\times 3 \right)+1-4 \\
& \Rightarrow A=1500+1-4 \\
\end{align}\]
According to BODMAS rule, now in A addition takes place.
\[\begin{align}
& \Rightarrow A=\left( 1500+1 \right)-4 \\
& \Rightarrow A=1501-4 \\
& \Rightarrow A=1497...(2) \\
\end{align}\]
From equation (1) and (2), we can say that
\[\Rightarrow 500\times 3+6\div 6-4=1497..(3)\]
So, from equation (3) it is clear that the value of \[500\times 3+6\div 6-4\] is equal to 1497.
Note: Students may have misconception that that the brackets are placed in the order of subtraction, addition, multiplication and division. If this misconception is followed, then
So, let us assume the value of \[500\times 3+6\div 6-4\] is equal to A.
\[\Rightarrow A=500\times 3+6\div 6-4....(1)\]
According to BODMAS rule, in A first subtraction takes place.
\[\begin{align}
& \Rightarrow A=500\times 3+6\div \left( 6-4 \right) \\
& \Rightarrow A=500\times 3+6\div 2 \\
\end{align}\]
According to BODMAS rule, now in addition takes place.
\[\begin{align}
& \Rightarrow A=500\times \left( 3+6 \right)\div 2 \\
& \Rightarrow A=500\times 9\div 2 \\
\end{align}\]
According to BODMAS rule, now in A multiplication takes place.
\[\begin{align}
& \Rightarrow A=\left( 500\times 9 \right)\div 2 \\
& \Rightarrow A=4500\div 2 \\
& \Rightarrow A=2250....(2) \\
\end{align}\]
From equation (1) and (2), we can say that
\[\Rightarrow 500\times 3+6\div 6-4=2250....(3)\]
So, from equation (3) it is clear that the value of \[500\times 3+6\div 6-4\] is equal to 2250 but we know that the value of \[500\times 3+6\div 6-4\] is equal to 1497. So, this misconception should be avoided by students to get a correct answer without any interruption. Hence, students should have a clear view of the concept.
Complete step by step answer:
Before solving this problem, we should know about the BODMAS rule. According to BODMAS rule, it is clear that the brackets are placed in the order of division, multiplication, addition and subtraction.
So, let us assume the value of \[500\times 3+6\div 6-4\] is equal to A.
\[\Rightarrow A=500\times 3+6\div 6-4....(1)\]
According to BODMAS rule, in A first division takes place.
\[\begin{align}
& \Rightarrow A=500\times 3+\left( 6\div 6 \right)-4 \\
& \Rightarrow A=500\times 3+1-4 \\
\end{align}\]
According to BODMAS rule, now in A multiplication takes place.
\[\begin{align}
& \Rightarrow A=\left( 500\times 3 \right)+1-4 \\
& \Rightarrow A=1500+1-4 \\
\end{align}\]
According to BODMAS rule, now in A addition takes place.
\[\begin{align}
& \Rightarrow A=\left( 1500+1 \right)-4 \\
& \Rightarrow A=1501-4 \\
& \Rightarrow A=1497...(2) \\
\end{align}\]
From equation (1) and (2), we can say that
\[\Rightarrow 500\times 3+6\div 6-4=1497..(3)\]
So, from equation (3) it is clear that the value of \[500\times 3+6\div 6-4\] is equal to 1497.
Note: Students may have misconception that that the brackets are placed in the order of subtraction, addition, multiplication and division. If this misconception is followed, then
So, let us assume the value of \[500\times 3+6\div 6-4\] is equal to A.
\[\Rightarrow A=500\times 3+6\div 6-4....(1)\]
According to BODMAS rule, in A first subtraction takes place.
\[\begin{align}
& \Rightarrow A=500\times 3+6\div \left( 6-4 \right) \\
& \Rightarrow A=500\times 3+6\div 2 \\
\end{align}\]
According to BODMAS rule, now in addition takes place.
\[\begin{align}
& \Rightarrow A=500\times \left( 3+6 \right)\div 2 \\
& \Rightarrow A=500\times 9\div 2 \\
\end{align}\]
According to BODMAS rule, now in A multiplication takes place.
\[\begin{align}
& \Rightarrow A=\left( 500\times 9 \right)\div 2 \\
& \Rightarrow A=4500\div 2 \\
& \Rightarrow A=2250....(2) \\
\end{align}\]
From equation (1) and (2), we can say that
\[\Rightarrow 500\times 3+6\div 6-4=2250....(3)\]
So, from equation (3) it is clear that the value of \[500\times 3+6\div 6-4\] is equal to 2250 but we know that the value of \[500\times 3+6\div 6-4\] is equal to 1497. So, this misconception should be avoided by students to get a correct answer without any interruption. Hence, students should have a clear view of the concept.
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