Answer
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Hint: To solve the given expression, we are going to first of all cut the 0 which is present in the numerator and the denominator. Then as you can see, we can divide the numerator and the denominator by 3. After that, we are going to divide the numerator and the denominator by 2. Lastly, we are going to multiply the remaining expression and get the final answer.
Complete step-by-step solution:
The expression given in the above problem is as follows:
$\dfrac{450\times 38}{60}$
As you can see that 0 is present in the numerator and the denominator so that 0 will get canceled out and we are left with:
$\dfrac{45\times 38}{6}$
Now, as you can see that the number 45 in the numerator is divisible by 3, and the number 6 in the denominator is also divided by 3 so we are going to divide the numerator and denominator by 3 we get,
$\dfrac{15\times 38}{2}$
Now, in the numerator 38 is divisible by 2 and in the denominator 2 is already divisible by 2 and we get,
$\begin{align}
& \dfrac{15\times 19}{1} \\
& =15\times 19 \\
\end{align}$
After that, we are going to multiply the two above numbers and we get,
$=285$
From the above solution, we have solved the given expression and the answer to the solution is 285.
Note: To solve such kinds of problems, first of all, remove the zeros written in the numerator and the denominator. Then, we are going to find the common factors among the numerator and the denominator. And lastly, multiply the remains present in the numerator and the denominator.
Complete step-by-step solution:
The expression given in the above problem is as follows:
$\dfrac{450\times 38}{60}$
As you can see that 0 is present in the numerator and the denominator so that 0 will get canceled out and we are left with:
$\dfrac{45\times 38}{6}$
Now, as you can see that the number 45 in the numerator is divisible by 3, and the number 6 in the denominator is also divided by 3 so we are going to divide the numerator and denominator by 3 we get,
$\dfrac{15\times 38}{2}$
Now, in the numerator 38 is divisible by 2 and in the denominator 2 is already divisible by 2 and we get,
$\begin{align}
& \dfrac{15\times 19}{1} \\
& =15\times 19 \\
\end{align}$
After that, we are going to multiply the two above numbers and we get,
$=285$
From the above solution, we have solved the given expression and the answer to the solution is 285.
Note: To solve such kinds of problems, first of all, remove the zeros written in the numerator and the denominator. Then, we are going to find the common factors among the numerator and the denominator. And lastly, multiply the remains present in the numerator and the denominator.
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