
How do you solve the equation $2x-5=x+10$?
Answer
534k+ views
Hint: Now we know that the given equation is a linear equation in one variable. Hence to solve the equation we will first separate all the variables and constants.
Complete step by step solution:
Now consider the given equation $2x-5=x+10$
Now we let us first shift the term x on RHS to LHS.
Hence we get $2x-x-5=10$ .
Now we know that 2x – x = x.
Hence we get the equation as $x-5=10$
Now let us shift 5 from LHS to RHS. Hence we get the equation as $x=10+5$
Hence on simplifying the above equation we get the required value of x as x = 15.
Hence the solution of the given equation is x = 15.
Note: Now note that while solving linear equations always bring the variables on one side and constant on the other side. If we have mixed fractions in the equation, first simplify the mixed fraction and then eliminate the fraction by taking LCM of the denominator and multiplying the whole equation with LCM.
Complete step by step solution:
Now consider the given equation $2x-5=x+10$
Now we let us first shift the term x on RHS to LHS.
Hence we get $2x-x-5=10$ .
Now we know that 2x – x = x.
Hence we get the equation as $x-5=10$
Now let us shift 5 from LHS to RHS. Hence we get the equation as $x=10+5$
Hence on simplifying the above equation we get the required value of x as x = 15.
Hence the solution of the given equation is x = 15.
Note: Now note that while solving linear equations always bring the variables on one side and constant on the other side. If we have mixed fractions in the equation, first simplify the mixed fraction and then eliminate the fraction by taking LCM of the denominator and multiplying the whole equation with LCM.
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