
Solve the equation \[10x = 30\] for the value of x.
Answer
488.7k+ views
Hint: Here we have a simple linear equation with one variable. We need to find the value of ‘x’. We can solve this using the transposition method that is by dividing the whole equation by 10. Since it is a simple equation we can give random values for x, that is \[x = 1,2,3,......\]. If L.H.S is equal to R.H.S then the substituted value is our answer.
Complete step-by-step solution:
Given, \[10x = 30\].
We transpose \[10\] which is present in the left-hand side of the equation to the right-hand side of the equation by dividing \[10\] on the right-hand side of the equation.
\[x = \dfrac{{30}}{{10}}\]
We can see that the variable ‘x’ and the constants are separated, then
\[ \Rightarrow x = 3\] is the required result.
Note: We can also solve this by giving the random values for x. Let substitute \[x = 1\] in the given equation.
\[10 \times 1 = 30\]
\[10 = 30\], Which is not true
Now give \[x = 2\]
\[10 \times 2 = 30\]
\[20 = 30\] , Which is not true.
Now give \[x = 3\]
\[10 \times 3 = 30\]
\[30 = 30\] , Which is true. Hence \[ \Rightarrow x = 3\] is the required result.
If we have addition, we use subtraction to transpose and wise versa. Similarly, if we have multiplication, we use division to transpose. If we have division, we use multiplication to transpose. Follow the same procedure for these kinds of problems.
Complete step-by-step solution:
Given, \[10x = 30\].
We transpose \[10\] which is present in the left-hand side of the equation to the right-hand side of the equation by dividing \[10\] on the right-hand side of the equation.
\[x = \dfrac{{30}}{{10}}\]
We can see that the variable ‘x’ and the constants are separated, then
\[ \Rightarrow x = 3\] is the required result.
Note: We can also solve this by giving the random values for x. Let substitute \[x = 1\] in the given equation.
\[10 \times 1 = 30\]
\[10 = 30\], Which is not true
Now give \[x = 2\]
\[10 \times 2 = 30\]
\[20 = 30\] , Which is not true.
Now give \[x = 3\]
\[10 \times 3 = 30\]
\[30 = 30\] , Which is true. Hence \[ \Rightarrow x = 3\] is the required result.
If we have addition, we use subtraction to transpose and wise versa. Similarly, if we have multiplication, we use division to transpose. If we have division, we use multiplication to transpose. Follow the same procedure for these kinds of problems.
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