
How do you solve the algebraic expression $ 49-\left( 3+10y-4\left( y+2 \right) \right)=-5\left( 3y-6 \right)-\left( 5\left( y-1 \right)-9y+21 \right)$ ?
Answer
541.5k+ views
Hint: In order to do this question, you will first have to simplify the above equation. To simplify the question, you need to multiply the terms outside the brackets with the terms inside the brackets using the distribution law. After simplifying the equation, you just need to add or subtract the like terms to further simplify the equation and then finally you get the answer for y.
Complete step by step solution:
In order to do this question, you will first have to simplify the above equation. To simplify the question, you need to multiply the terms outside the brackets with the terms inside the brackets using the distribution law. Therefore, simplifying the equation, we get:
$ \Rightarrow 49-\left( 3+10y-4\left( y+2 \right) \right)=-5\left( 3y-6 \right)-\left( 5\left( y-1 \right)-9y+21 \right)$
$ \Rightarrow 49-3-10y-4y-8=-15y+30-5y+5+9y-21$
$ \Rightarrow 38-14y=-11y+14$
$ \Rightarrow 3y=24$
$ \Rightarrow y=8$
From here, we can see that we got the answer for y as 8.
Therefore the final answer for the question How do you solve $ 49-\left( 3+10y-4\left( y+2 \right) \right)=-5\left( 3y-6 \right)-\left( 5\left( y-1 \right)-9y+21 \right)$ is y=8.
Note: To do this question, you do not need to know any formulas. You just need to multiply the terms outside the brackets with the terms inside the brackets using the distribution law. You need to be careful while doing the substitutions, otherwise you may get the wrong answer in the end. To verify, if you got the correct answer, you can substitute the answer, that is the value of y in the questions. If you get that right hand side is equal to left hand side, then you got the correct answer, otherwise you have to check where you went wrong.
Complete step by step solution:
In order to do this question, you will first have to simplify the above equation. To simplify the question, you need to multiply the terms outside the brackets with the terms inside the brackets using the distribution law. Therefore, simplifying the equation, we get:
$ \Rightarrow 49-\left( 3+10y-4\left( y+2 \right) \right)=-5\left( 3y-6 \right)-\left( 5\left( y-1 \right)-9y+21 \right)$
$ \Rightarrow 49-3-10y-4y-8=-15y+30-5y+5+9y-21$
$ \Rightarrow 38-14y=-11y+14$
$ \Rightarrow 3y=24$
$ \Rightarrow y=8$
From here, we can see that we got the answer for y as 8.
Therefore the final answer for the question How do you solve $ 49-\left( 3+10y-4\left( y+2 \right) \right)=-5\left( 3y-6 \right)-\left( 5\left( y-1 \right)-9y+21 \right)$ is y=8.
Note: To do this question, you do not need to know any formulas. You just need to multiply the terms outside the brackets with the terms inside the brackets using the distribution law. You need to be careful while doing the substitutions, otherwise you may get the wrong answer in the end. To verify, if you got the correct answer, you can substitute the answer, that is the value of y in the questions. If you get that right hand side is equal to left hand side, then you got the correct answer, otherwise you have to check where you went wrong.
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