
How do you solve ${{\sin }^{2}}x-1=0$ and find all exact general solutions?
Answer
551.4k+ views
Hint: First of all we have to solve the given expression and then find the range of function and after that we have to use arithmetic progression to solve the expression to get the general solution.
Complete step by step answer:
Given that
${{\sin }^{2}}x-1=0$
We know that
${{a}^{2}}-{{b}^{2}}=\left( a+b \right)\left( a-b \right)$
Therefore, the given expression may be written as
${{\sin }^{2}}x-1=\left( 1+\sin x \right)\left( \sin x-1 \right)$
Therefore,
$\left( 1+\sin x \right)\left( \sin x-1 \right)=0$
Now solve the above expression in parts
$\left( 1+\sin x \right)=0$
$\Rightarrow \sin x=-1$
From above expression we get
$x=\dfrac{3\pi }{2},\dfrac{7\pi }{2},....$
And
$\sin x-1=0$
$\Rightarrow \sin x=1$
From above expression we get
$x=\dfrac{\pi }{2},\dfrac{5\pi }{2},....$
Now we get
$x=\dfrac{\pi }{2},\dfrac{3\pi }{2},\dfrac{5\pi }{2},...$
Now to final answer we have to use the arithmetic progression
Here,
$a=\dfrac{\pi }{2}$
And
$d=\pi $
We know that the formula of arithmetic progression is as follows:
${{T}_{n}}=\dfrac{\pi }{2}+\left( n-1 \right)\pi $
Further solving the above expression we get
${{T}_{n}}=\left( \dfrac{1}{2}+n-1 \right)\pi $
Further solving
${{T}_{n}}=\left( n-\dfrac{1}{2} \right)\pi $
And
${{T}_{n}}=\left( 2n-1 \right)\dfrac{\pi }{2}$
Therefore, the exact general solution of the given problem is
${{T}_{n}}=\left( n-\dfrac{1}{2} \right)\pi $
And
${{T}_{n}}=\left( 2n-1 \right)\dfrac{\pi }{2}$
Additional information:
In these questions we have to find the range of the given function by the trigonometric method in which the function lies. After finding all the ranges we can find the exact solutions of the problem.
Note:
In such a type of question it is very important to understand the question about what the question is asking. After understanding this it is really important for us to find out the range of the function correctly. Because if we calculate the wrong range of the function the whole solution goes wrong. After that we have to combine the ranges by arithmetic progression method to get the exact solution. So it is also important to remember the formula of arithmetic progression.
Complete step by step answer:
Given that
${{\sin }^{2}}x-1=0$
We know that
${{a}^{2}}-{{b}^{2}}=\left( a+b \right)\left( a-b \right)$
Therefore, the given expression may be written as
${{\sin }^{2}}x-1=\left( 1+\sin x \right)\left( \sin x-1 \right)$
Therefore,
$\left( 1+\sin x \right)\left( \sin x-1 \right)=0$
Now solve the above expression in parts
$\left( 1+\sin x \right)=0$
$\Rightarrow \sin x=-1$
From above expression we get
$x=\dfrac{3\pi }{2},\dfrac{7\pi }{2},....$
And
$\sin x-1=0$
$\Rightarrow \sin x=1$
From above expression we get
$x=\dfrac{\pi }{2},\dfrac{5\pi }{2},....$
Now we get
$x=\dfrac{\pi }{2},\dfrac{3\pi }{2},\dfrac{5\pi }{2},...$
Now to final answer we have to use the arithmetic progression
Here,
$a=\dfrac{\pi }{2}$
And
$d=\pi $
We know that the formula of arithmetic progression is as follows:
${{T}_{n}}=\dfrac{\pi }{2}+\left( n-1 \right)\pi $
Further solving the above expression we get
${{T}_{n}}=\left( \dfrac{1}{2}+n-1 \right)\pi $
Further solving
${{T}_{n}}=\left( n-\dfrac{1}{2} \right)\pi $
And
${{T}_{n}}=\left( 2n-1 \right)\dfrac{\pi }{2}$
Therefore, the exact general solution of the given problem is
${{T}_{n}}=\left( n-\dfrac{1}{2} \right)\pi $
And
${{T}_{n}}=\left( 2n-1 \right)\dfrac{\pi }{2}$
Additional information:
In these questions we have to find the range of the given function by the trigonometric method in which the function lies. After finding all the ranges we can find the exact solutions of the problem.
Note:
In such a type of question it is very important to understand the question about what the question is asking. After understanding this it is really important for us to find out the range of the function correctly. Because if we calculate the wrong range of the function the whole solution goes wrong. After that we have to combine the ranges by arithmetic progression method to get the exact solution. So it is also important to remember the formula of arithmetic progression.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

10 examples of friction in our daily life

