
How do you solve ${p^2} - 4p + 4 = 0$ using the quadratic formula?
Answer
536.1k+ views
Hint: To solve this problem we should know about quadratic equations and quadratic formulas.
Quadratic equation: It is any equation that can be rearranged in standard form as $a{x^2} + bx + c = 0$ where $x$ is represent a unknown and $a,b\,and\,c$ represent known number, where $a \ne 0$ if $a = 0$ then it will change into a linear equation.
Quadratic formula: The formula that is used to calculate the solution of a quadratic equation.
Let quadratic equation is $a{x^2} + bx + c = 0$ then its solution will be,
$x = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}$
Complete step by step solution:
As given in question ${p^2} - 4p + 4 = 0$ .
Compare it with $a{x^2} + bx + c = 0$ to calculate the value of $a,b\,and\,c$ .
We get, $a = 1,b = - 4\,and\,c = 4$
As we know, the quadratic formula is used to find the roots of a quadratic equation.
So, keeping value in the quadratic equation. We get,
${x_{1,2}} = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}$
$ \Rightarrow {x_{1,2}} = \dfrac{{ - ( - 4) \pm \sqrt {{{( - 4)}^2} - 4.1.4} }}{{2.1}}$
By further solving it. We get,
$ \Rightarrow {x_{1,2}} = \dfrac{{4 \pm \sqrt {16 - 16} }}{2} = \dfrac{4}{2} = 2$
From the above calculation. We get
The roots of the quadratic equation will be the same, that is $x = 2$ .
Note: We can also do this quadratic equation by factorization by grouping which is also a suitable and easiest method. The quadratic equation is used in our daily life like applied physics, engineering and research and development. When we throw a ball its motion is parabolic whose path will be calculated by using a quadratic equation. So, so much machinery in defense is based on it.
Quadratic equation: It is any equation that can be rearranged in standard form as $a{x^2} + bx + c = 0$ where $x$ is represent a unknown and $a,b\,and\,c$ represent known number, where $a \ne 0$ if $a = 0$ then it will change into a linear equation.
Quadratic formula: The formula that is used to calculate the solution of a quadratic equation.
Let quadratic equation is $a{x^2} + bx + c = 0$ then its solution will be,
$x = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}$
Complete step by step solution:
As given in question ${p^2} - 4p + 4 = 0$ .
Compare it with $a{x^2} + bx + c = 0$ to calculate the value of $a,b\,and\,c$ .
We get, $a = 1,b = - 4\,and\,c = 4$
As we know, the quadratic formula is used to find the roots of a quadratic equation.
So, keeping value in the quadratic equation. We get,
${x_{1,2}} = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}$
$ \Rightarrow {x_{1,2}} = \dfrac{{ - ( - 4) \pm \sqrt {{{( - 4)}^2} - 4.1.4} }}{{2.1}}$
By further solving it. We get,
$ \Rightarrow {x_{1,2}} = \dfrac{{4 \pm \sqrt {16 - 16} }}{2} = \dfrac{4}{2} = 2$
From the above calculation. We get
The roots of the quadratic equation will be the same, that is $x = 2$ .
Note: We can also do this quadratic equation by factorization by grouping which is also a suitable and easiest method. The quadratic equation is used in our daily life like applied physics, engineering and research and development. When we throw a ball its motion is parabolic whose path will be calculated by using a quadratic equation. So, so much machinery in defense is based on it.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Explain zero factorial class 11 maths CBSE

What organs are located on the left side of your body class 11 biology CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

