
How do you solve inequalities $5 - 3c \leqslant c + 17$ ?
Answer
548.4k+ views
Hint: For the given inequality $5 - 3c \leqslant c + 17$ , we have to solve for $c$ . We just need to remember to apply all of our operations to both the parts, like adding , subtracting , multiplying, and dividing . Signs get reversed only when we multiply or divide each side by a negative number.
Complete step by step solution:
The given inequality is $5 - 3c \leqslant c + 17$ .
We just need to remember to apply all of our operations to both the parts.
Subtract $ - 5$ from both the side of the inequality ,
$ \Rightarrow 5 - 3c - 5 \leqslant c + 17 - 5$
$ \Rightarrow - 3c \leqslant c + 12$
We can also write it as ,
$ \Rightarrow c + 12 \geqslant - 3c$
Add $3c$both the side of the inequality ,
$ \Rightarrow c + 12 + 3c \geqslant - 3c + 3c$
$ \Rightarrow 4c + 12 \geqslant 0$
Subtract $12$ from both the side of the inequality ,
$ \Rightarrow 4c + 12 - 12 \geqslant - 12$
$ \Rightarrow 4c \geqslant - 12$
Divide both the side of the inequality by $4$,
$
\Rightarrow \dfrac{{4c}}{4} \geqslant \dfrac{{ - 12}}{4} \\
\Rightarrow c \geqslant - 3 \\
$
$ \Rightarrow c \geqslant - 3$
Therefore $c \in [ - 3,\infty )$ .
Additional Informational: Inequalities are often manipulated like equations and follow terribly similar rules, however there's one necessary exception. If you add constant variety to each side of given inequality , the inequality remains true. If you subtract constant variety from each side of the given inequality , the inequality remains true. If you multiply or divide each side of the given inequality by constant positive variety, the inequality remains true.
However, if you multiply or divide each side of the given inequality by a negative variety, the inequality isn't any longer true. In fact, the inequality becomes reversed. This can be quite simple to visualize as a result of we will write that $4 > 2$ . However, if we tend to multiply each side of this inequality by a negative number, we've got to reverse the inequality , giving $ - 4 < - 2$ in order for it to be true.
Note: In inequality:
i) You can add constant amount to every aspect
ii) You can subtract constant amount from both sides
iii) You can multiply or divide both sides by a constant positive amount .
iv) If you multiply or divide both sides by a negative amount, the inequality needs to be reversed.
Complete step by step solution:
The given inequality is $5 - 3c \leqslant c + 17$ .
We just need to remember to apply all of our operations to both the parts.
Subtract $ - 5$ from both the side of the inequality ,
$ \Rightarrow 5 - 3c - 5 \leqslant c + 17 - 5$
$ \Rightarrow - 3c \leqslant c + 12$
We can also write it as ,
$ \Rightarrow c + 12 \geqslant - 3c$
Add $3c$both the side of the inequality ,
$ \Rightarrow c + 12 + 3c \geqslant - 3c + 3c$
$ \Rightarrow 4c + 12 \geqslant 0$
Subtract $12$ from both the side of the inequality ,
$ \Rightarrow 4c + 12 - 12 \geqslant - 12$
$ \Rightarrow 4c \geqslant - 12$
Divide both the side of the inequality by $4$,
$
\Rightarrow \dfrac{{4c}}{4} \geqslant \dfrac{{ - 12}}{4} \\
\Rightarrow c \geqslant - 3 \\
$
$ \Rightarrow c \geqslant - 3$
Therefore $c \in [ - 3,\infty )$ .
Additional Informational: Inequalities are often manipulated like equations and follow terribly similar rules, however there's one necessary exception. If you add constant variety to each side of given inequality , the inequality remains true. If you subtract constant variety from each side of the given inequality , the inequality remains true. If you multiply or divide each side of the given inequality by constant positive variety, the inequality remains true.
However, if you multiply or divide each side of the given inequality by a negative variety, the inequality isn't any longer true. In fact, the inequality becomes reversed. This can be quite simple to visualize as a result of we will write that $4 > 2$ . However, if we tend to multiply each side of this inequality by a negative number, we've got to reverse the inequality , giving $ - 4 < - 2$ in order for it to be true.
Note: In inequality:
i) You can add constant amount to every aspect
ii) You can subtract constant amount from both sides
iii) You can multiply or divide both sides by a constant positive amount .
iv) If you multiply or divide both sides by a negative amount, the inequality needs to be reversed.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

