
How do you solve for $c$ in $\dfrac{9}{c} = \dfrac{{27}}{{39}}$ ?
Answer
535.5k+ views
Hint: In the given question, we have been asked to find the value of ‘’ and it is given that $\dfrac{9}{c} = \dfrac{{27}}{{39}}$. To solve this question, we need to get ‘c’ on one side of the “equals” sign, and all the other numbers on the other side. To solve this equation for a given variable ‘c’, we have to undo the mathematical operations such as addition, subtraction, multiplication, and division that have been done to the variables.
Complete step-by-step solution:
We have given that,
$\Rightarrow \dfrac{9}{c} = \dfrac{{27}}{{39}}$
Now , multiply by $c$ to both the side of the equation ,
$ \Rightarrow c \times \dfrac{9}{c} = c \times \dfrac{{27}}{{39}}$
$ \Rightarrow 9 = \dfrac{{27c}}{{39}}$
Or $\dfrac{{27c}}{{39}} = 9$
Multiple by $39$ to both the side of the equation ,
$ \Rightarrow 39 \times \dfrac{{27c}}{{39}} = 39 \times 9$
\[ \Rightarrow 27c = 39 \times 9\]
Divide by $27$ to both the side of the equation ,
\[
\Rightarrow \dfrac{{27c}}{{27}} = \dfrac{{39 \times 9}}{{27}} \\
\Rightarrow c = 13 \\
\]
Therefore, the value of $c$ is equal to $13$ .
It is the required answer.
Additional information: In the given question, no mathematical formula is being used only the mathematical operations such as addition, subtraction, multiplication and division are used. Use addition or subtraction properties of equality to gather variable terms on one side of the equation and constant on the other side of the equation. Use the multiplication or division properties of equality to form the coefficient of the variable term equivalent to one.
Note: The important thing to recollect about any equation is that the ‘equals’ sign represents a balance. What the sign says is that what’s on the left-hand side is strictly an equal to what’s on the right-hand side. It is the type of question where only mathematical operations such as addition, subtraction, multiplication and division is used.
Complete step-by-step solution:
We have given that,
$\Rightarrow \dfrac{9}{c} = \dfrac{{27}}{{39}}$
Now , multiply by $c$ to both the side of the equation ,
$ \Rightarrow c \times \dfrac{9}{c} = c \times \dfrac{{27}}{{39}}$
$ \Rightarrow 9 = \dfrac{{27c}}{{39}}$
Or $\dfrac{{27c}}{{39}} = 9$
Multiple by $39$ to both the side of the equation ,
$ \Rightarrow 39 \times \dfrac{{27c}}{{39}} = 39 \times 9$
\[ \Rightarrow 27c = 39 \times 9\]
Divide by $27$ to both the side of the equation ,
\[
\Rightarrow \dfrac{{27c}}{{27}} = \dfrac{{39 \times 9}}{{27}} \\
\Rightarrow c = 13 \\
\]
Therefore, the value of $c$ is equal to $13$ .
It is the required answer.
Additional information: In the given question, no mathematical formula is being used only the mathematical operations such as addition, subtraction, multiplication and division are used. Use addition or subtraction properties of equality to gather variable terms on one side of the equation and constant on the other side of the equation. Use the multiplication or division properties of equality to form the coefficient of the variable term equivalent to one.
Note: The important thing to recollect about any equation is that the ‘equals’ sign represents a balance. What the sign says is that what’s on the left-hand side is strictly an equal to what’s on the right-hand side. It is the type of question where only mathematical operations such as addition, subtraction, multiplication and division is used.
Recently Updated Pages
Master Class 8 Maths: Engaging Questions & Answers for Success

Class 8 Question and Answer - Your Ultimate Solutions Guide

Master Class 7 Maths: Engaging Questions & Answers for Success

Class 7 Question and Answer - Your Ultimate Solutions Guide

Master Class 6 Maths: Engaging Questions & Answers for Success

Class 6 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Which of the following does not have a fundamental class 10 physics CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

